(10y - 4) + (7y + 8) + (7y - 5) + (4y - 5) =
= 10y - 4 + 7y + 8 + 7y - 5 + 4y - 5 =
= 10y + 7y + 7y + 4y - 4 + 8 - 5 - 5 = <u>2</u><u>8</u><u>y</u><u> </u><u>-</u><u> </u><u>6</u>
<span>10!/5! =10*9*8*7*6=30,240;;
If order is not considered, 10C5 =10!/5!5!=252 </span>
Answer:
True
Step-by-step explanation:
No, because (2,0) is a coordinate. x=2 and y=0. So just plug in the numbers where there's x or y with the appropriate number, (2 or 0). So in the first equation, x-2y=0, when you pug in the numbers, 2-2(0)=0, you know it's wrong because 2-0=0 isn't correct. So no. the point (2,0) is not a solution to the first equation. Now plug in the numbers for the second coordinate. You get 2(2)-3(0)=1. So 4-0=1. This is once again false no no. (2,0) satisfies neither equations.
