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3 years ago

HELP PLEASE!!!

Mathematics

2 answers:

lisabon 2012 [21]3 years ago

6 0

Answer:

C Multiply the 1st equation by 2

Step-by-step explanation:

-6y + 6y = 0

8_murik_8 [283]3 years ago

6 0

Answer:

C Multiply the 1st equation by 2

Step-by-step explanation:

5x-3y=10

2(5x-3y=10)

10x-6y

if you have a positive 6y and a negative 6y you can then eliminate

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Step-by-step explanation:

Here will be the function if it went up:

20000(1+0.0475)^20

Here’s if it went down:

20000(1-0.0475)^20

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3 years ago

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3 years ago

Which fraction is the simplest form of 16/34

Alex_Xolod [135]

Answer:

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3 years ago

Read 2 more answers

If 30,000 cm2 of material is available to make a box with a square base and an open top, what is the largest possible volume (in

Cloud [144]

Answer:

The largest possible volume of the box is 2000000 cubic meters.

Step-by-step explanation:

The volume ( $V$ ), in cubic centimeters, and surface area ( $A_{s}$ ), in square centimeters, of the box with a square base are described below:

$A_{s} = l^{2}+h\cdot l$ (1)

$V = l^{2}\cdot h$ (2)

Where:

$l$ - Side length of the base, in centimeters.

$h$ - Height of the box, in centimeters.

By (2), we clear $h$ within the formula:

$h = \frac{V}{l^{2}}$

And we apply in (1) and simplify the resulting expression:

$A_{s} = l^{2}+ \frac{V}{l}$

$A_{s}\cdot l = l^{3}+V$

$V = A_{s}\cdot l -l^{3}$ (3)

Then, we find the first and second derivatives of this expression:

$V' = A_{s}-3\cdot l^{2}$ (4)

$V'' = -6\cdot l$ (5)

If $V' = 0$ and $A_{s} = 30000\,cm^{2}$ , then we find the critical value of the side length of the base is:

$30000-3\cdot l^{2} = 0$

$3\cdot l^{2} = 30000$

$l = 100\,cm$

Then, we evaluate this result in the expression of the second derivative:

$V'' = -600$

By Second Derivative Test, we conclude that critical value leads to an absolute maximum. The maximum possible volume of the box is:

$V = 30000\cdot l - l^{3}$

$V = 2000000\,cm^{3}$

The largest possible volume of the box is 2000000 cubic meters.

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3 years ago