All categories

2 years ago

8x + 2x - 5 = -35 Can someone help me with this answer and how to show my work?

1 answer:

7 0

The answer is X= -3 and the work is 8x+2x-5= -35 so the -5 turns to a positive 5 and cancels itself it out so -35 becomes -30 then you add 8x and 2x then you get get 10x then you divide -30 by 10 and you get -3

You might be interested in

At Freddy’s fro yo shop 25 percent of the 44 frozen yogurt flavors are sugar free how many frozen yogurt flavors are sugar free

daser333 [38]

25%of44=11 .so 11 frozen yogurt flavours are sugar free

6 0

1 year ago

What is the measure of angle XWY?

motikmotik

According to the vertical angle theorem when two lines intersects each other, the vertical angles that are formed are congruent to each other.

So, angle XWY is 74 degrees.

Hope this helps! Mark as Brainliest please! :)))

8 0

2 years ago

Please help!!

valkas [14]

A calculator can show you the answer to these very quickly.

$\dfrac{7.488\cdot 10^{-8}}{3.12\cdot 10^{2}}=\dfrac{7.488}{3.12}\times 10^{(-8-2)}\\\\=2.4\cdot 10^{-10}$

5 0

2 years ago

How do you rewrite quadratic equations

disa [49]

A quadratic should be in the form ax²+bx+c=0
where a b and c are all numbers

8 0

2 years ago

The weights of a certain dog breed are approximately normally distributed with a mean of μ = 55 pounds, and a standard deviation

weqwewe [10]

Answer:

(a)z=-1

(b)48.5 pounds

Step-by-step explanation:

$z-score=\dfrac{x-\mu}{\sigma}$

Given:

Mean, μ = 55 pounds

Standard deviation,σ = 6 pounds.

(a)For a dog that weighs 49 pounds.

x=49 pounds

The z-score

$=\dfrac{49-55}{6}\\=\dfrac{-6}{6}\\\\=-1$

(b)When a dog has a z-score of -1.09

$-1.09=\dfrac{x-55}{6}\\x-55=-6.54\\x=55-6.54\\x=48.46 \approx 48.5$ pounds (to the nearest tenth)$

The weight of a dog with a z-score of -1.09 is 48.5 pounds.

(c)When a dog has a z-score of 1.09

$1.09=\dfrac{x-55}{6}\\x-55=6.54\\x=55+6.54\\x=61.54 \approx 61.5$ pounds (to the nearest tenth)$

The weight of a dog with a z-score of 1.09 is 61.5 pounds.

3 0

2 years ago