Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
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Problem 10
<h3>Answer: approximately 57.39159 km</h3>
Explanation: You'll use the equation cos(28) = d/65 to solve for d to get d = 65*cos(28) = 57.39159 approximately. We use the cosine ratio because it ties together the adjacent and hypotenuse.
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Problem 11
<h3>Answer: approximately 10.46162 meters </h3>
Explanation: This time we use the sine rule. We have the height as the opposite side (which is unknown, call it x) and the hypotenuse is the ladders length (11). So we have sin(72) = x/11 which solves to x = 11*sin(72) = 10.46162
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Problem 12
<h3>Answer: approximately 16.05724 cm</h3>
Explanation: Now we use the tangent rule to connect the opposite and adjacent sides.
tan(37) = 12.1/x
x*tan(37) = 12.1
x = 12.1/tan(37)
x = 16.05724 approximately
Answer:
m = -0.8
Step-by-step explanation:
Use slope formula: (y2 - y1) / (x2 - x1)
Apply formula: ( 8 ) / (-10)
Simplify: -4 / 5
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3/4 is 0.75.
3/4 is larger than 0.7
Answer:
He does not divide the numerator and the denominator by the same number. Nicholas divides 20 by 5 and 30 by 6. He ought to have divided 30 by 5 as well and then simplified.
P.S. Nicholas should have just divided both 20 and 30 by 10 to simplify in one step
