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sladkih [1.3K]
3 years ago
12

Cheryl collected data for her mathematics project. She noted that the data set was approximately normal. Select the statement th

at is always true if Cheryl replaces the maximum data value with a value that was an extremely high outlier.
A. Mean would increase.
B. Interquartile range would increase.
C. Standard deviation would remain the same.
D. The data set would remain approximately normal.
Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
8 0

Answer:

MEAN WOULD INCREASE

Step-by-step explanation:

THE AVERAGE IS INCREASED

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I don’t know how to do this, what’s the area?
Anastaziya [24]

Answer:

Hello!

Step-by-step explanation:

To find the area of a triangle, multiply the base by the height, and then divide by 2. The division by 2 comes from the fact that a parallelogram can be divided into 2 triangles. For example, in the diagram to the left, the area of each triangle is equal to one-half the area of the parallelogram.

So,you have to multiply.

Hope this helps.

6 0
3 years ago
SOMEONE PLEASE HELP
otez555 [7]

Answer: c and e

Step-by-step explanation:

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3 years ago
The midpoint of AB is at (3,7) and A is at (0,-5). Where is B located?
olga nikolaevna [1]
\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ \square }}\quad ,&{{ \square }})\quad 
%  (c,d)
&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)\qquad thus
\\
----------------------------\\\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
A&({{ 0}}\quad ,&{{ -5}})\quad 
%  (c,d)
B&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
%   coordinates of midpoint 
(3,7)\impliedby midpoint\qquad thus
\\ \quad \\
\left(\cfrac{{{ x_2 }} + {{ 0}}}{2}=3\quad ,\quad \cfrac{{{ y_2 }} + {{( -5)}}}{2}=7 \right)\to 
\begin{cases}
\cfrac{{{ x_2 }} + {{ 0}}}{2}=3
\\ \quad \\
\cfrac{{{ y_2 }} + {{ -5}}}{2}=7
\end{cases}
\\ \quad \\
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3 0
3 years ago
Write the number in expanded form 68,020
allochka39001 [22]

Standard Form:

68,020

Expanded Notation Form:

 68,020 =

 60,000  

+ 8,000  

+ 0  

+ 20  

+ 0  

Expanded Factors Form:

   68,020 =

 6 × 10,000  

+ 8 × 1,000  

+ 0 × 100  

+ 2 × 10  

+ 0 × 1  

Expanded Exponential Form:

 68,020 =

       6 × 10^4

+ 8 × 10^3

+ 0 × 10^2

+ 2 × 10^1

+ 0 × 10^0

Word Form:

68,020 =

sixty-eight thousand twenty

4 0
3 years ago
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lilavasa [31]

Answer:

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Step-by-step explanation:

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