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IRISSAK [1]
3 years ago
10

What is the mean, median and mode for a data set of 50,42,55,38,40,55,and 61​

Mathematics
1 answer:
nlexa [21]3 years ago
5 0
Mean: 48.7
Median: 38
Mode:55
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4 years ago
Looking to solve (Ac+b-d)(a^2-c)=
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It should be noted that the expansion of the equation (ac+b-d)(a² - c) will be a³c + ac² + a²b - bc - a²d + cd.

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6 0
1 year ago
Find the area of the triangle<br> 1. C=110 degrees, a=6, b=10<br> 2. B=130 degrees, a=92, c=30
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1.\ \ \ |\angle \ ACB|=110^0\\\\.\ \ \ \ \ a=|BC|=6\ [u]\ \ \ and\ \ \ b=|AC|=10\ [u]\\\\Area= \frac{1}{2} \cdot |AC|\cdot |BC|\cdot sin(|\angle \ ACB|)\\\\Area= \frac{1}{2} \cdot 6\cdot 10\cdot sin110^0=30\cdot sin (180^0-70^0)=\\\\.\ \ \ \ \ \ =30\cdot sin70^0\approx30\cdot 0.9397=28.191\ [u^2]\\\\

2.\ \ \ |\angle \ ABC|=130^0\\\\.\ \ \ \ \ a=|BC|=92\ [u]\ \ \ and\ \ \ c=|AB|=30\ [u]\\\\Area= \frac{1}{2} \cdot |AB|\cdot |BC|\cdot sin(|\angle \ ABC|)\\\\Area= \frac{1}{2} \cdot 30\cdot 92\cdot sin130^0=1380\cdot sin (180^0-50^0)=\\\\.\ \ \ \ \ \ =1380\cdot sin50^0\approx1380\cdot 0.7660=1057.08\ [u^2]\\\\
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3 years ago
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