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3 years ago

point M with coordinates (3,4) is the midpoint of the line AB and A has the point (-1,6). what is the point of B?

Mathematics

1 answer:

irina [24]3 years ago

4 0

Answer:

B = (7, 2)

Step-by-step explanation:

B = 2M -A

B = 2(3, 4) -(-1, 6) = (2·3-(-1), 2·4-6)

B = (7, 2)

_____

The expression for the other end point, B, comes from the equation for the midpoint.

M = (A +B)/2

2M = A + B . . . . . multiply by 2

2M -A = B . . . . . . subtract A to get an expression for B

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3 years ago

Find a vector parametrization for the line with the given description. Perpendicular to the yz-plane, passes through (0, 0, 8)

Brilliant_brown [7]

Answer:

$\left\{\begin{array}{l}x=t\\ \\y=0\\ \\z=8\end{array}\right.$

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Step-by-step explanation:

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Write a vector parametrization for this line

$\left\{\begin{array}{l}\dfrac{x-0}{1}=t\\ \\\dfrac{y-0}{0}=t\\ \\\dfrac{z-8}{0}=t\end{array}\right.\Rightarrow \left\{\begin{array}{l}x=t\\ \\y=0\\ \\z=8\end{array}\right.$

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3 years ago

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