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baherus [9]
3 years ago
12

answer the questions about the given a reflection of quadrilateral ABCD onto quadrilateral ABCD the first one is done for you HE

LP PLEASE

Mathematics
1 answer:
Natalka [10]3 years ago
7 0
2. B(-5,6)
3. C’(3,7)
4. C’D’
5. angle D’
6. Reflected over the y axis
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Charra [1.4K]

Answer:

b. 0.50x+15=25

so the answer is 20

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3 years ago
Which graph represents the function y = 3*+2?
puteri [66]

Answer:

We can graph y = 2x/3 - 2 to find the line.

We know one point, which is the y-intercept. The y-intercept is (0,-2) so that is our first point. Plot that point on the chart. Now to find another point, we can just insert a number for x and solve for y. I am going to use the number 3.

y = 2x/3 - 2

y = 2(3)/3 - 2

y = 6/3 - 2

y = 2 - 2

y = 0

So when x = 3 y = 0. We have another point,which is (3,0) Plot the points (0, -2) (3, 0) and draw a line between the points and that is your graph.

there ya go

5 0
3 years ago
Divide. Round your answer to the nearest hundredth. 0.576 / 8.3
Nimfa-mama [501]

Answer:

0.069

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0.576/8.3 = 0.06939759036

4 0
3 years ago
4x+2y=2<br> 3x+y=4 explain how you got the answer pls answer it is a timed test
valina [46]

Answer:

1. if you solve for y you will get y=−2x+1 and if you solve for x then you get               x= −1 2 y+ 1 2

SECOND ONE IDK

7 0
4 years ago
Read 2 more answers
What is the volume of the solid whose cross- sections are circular disks perpendicular to the x-axis and with diameters on the r
12345 [234]

Answer:

the volume of the solid is \frac{\pi }{120}

Step-by-step explanation:

Given the data in the question;

y = x and y = x²

so

x = x²

x - x² = 0

Radius will be; r = ( x - x² )/2

Area of the circular disk πr² = π[ ( x - x² )/2 ]²

A = \frac{\pi }{4}( x - x² )²

So, our volume will be;

V = ₀∫¹ A(x) dx

we substitute

= ₀∫¹ \frac{\pi }{4}( x - x² )² dx        

{ lets expand; ( x - x² )² = x(x-x²) -x²(x-x²) = x² - x³ - x³ + x⁴ = x² + x⁴ - 2x³  }

so we have;

=  ₀∫¹ \frac{\pi }{4}( x² + x⁴ - 2x³ ) dx  

= \frac{\pi }{4} [ \frac{x^3}{3} + \frac{x^5}{5} - \frac{2}{4} x^4 ]^1_0

= \frac{\pi }{4}[ \frac{1}{3} + \frac{1}{5} - \frac{2}{4} ]

= \frac{\pi }{4}[ \frac{1}{30} ]

V = \frac{\pi }{120}

Therefore, the volume of the solid is \frac{\pi }{120}

6 0
3 years ago
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