Answer:
I cannot see the picture
Step-by-step explanation:
Answer:64 ounces
Step-by-step explanation:
average is 8 ounces per serving
According to the information given in the exercise:
• 1 meter of lightning cable weight 85 grams.
,
• An empty spool weighs 260 grams.
,
• Ted weighs the partly used spool shown in the picture and its total weight is 1540 grams.
Then, knowing this, let be "x" the number of meters of cable left on the spool.
You can set up the following using the information given in the exercise:

Knowing that:

You can set up that:

Therefore, solving for "x", you get:


Hence, you can conclude that the answer is: Second option.
The answer would be b hope this helps :)
Answer:
Mutually exclusive,

Step-by-step explanation:
Please consider the complete question:
Determine if the scenario involves mutually exclusive or overlapping events. Then find the probability.
A cooler contains twelve bottles of sports drink: four lemon-lime flavored, four orange flavored, and four fruit-punch flavored. You randomly grab a bottle. It is a lemon-lime or an orange.
Let us find probability of finding one lemon lime drink.



Let us find probability of finding one orange drink.



Since probability of choosing a lemon lime doesn't effect probability of choosing orange drink, therefore, both events are mutually exclusive.
We know that probability of two mutually exclusive events is equal to the sum of both probabilities.




Therefore, the probability of choosing a lemon lime or orange is
.