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2 years ago

Find (f • g)(-1). f(x) = x + 1 g(x) = x^2 + 5x

Mathematics

2 answers:

nydimaria [60]2 years ago

5 0

Answer:

Step-by-step explanation:

docker41 [41]2 years ago

3 0

Answer:

Step-by-step explanation:

(gf)(x)=(x+1)(x2+5x)

gf(x)=x3+5x2+x2+5x

gf(x)=x3+6x2+5x

gf(-1)=(-1)3+6(-1)2+5(-1)

gf(-1)=-1+6(1)-5

gf(-1)=-1+6-5

gf(-1)=6-6

gf(-1)=0

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3 years ago

1 meter lightining cable weight 85 grams empty spool weight is 260 gram he have total weight 1540gram what is the answer

mrs_skeptik [129]

According to the information given in the exercise:

• 1 meter of lightning cable weight 85 grams.

• An empty spool weighs 260 grams.

• Ted weighs the partly used spool shown in the picture and its total weight is 1540 grams.

Then, knowing this, let be "x" the number of meters of cable left on the spool.

You can set up the following using the information given in the exercise:

$Total\text{ }weight=Empty\text{ }spool+85(Meters\text{ }of\text{ }cable)$

Knowing that:

$\begin{gathered} Total\text{ }weight=1540 \\ Empty\text{ }spool=260 \end{gathered}$

You can set up that:

$1540=260+85x$

Therefore, solving for "x", you get:

$\begin{gathered} 1540-260=85x \\ \\ \frac{1540-260}{85}=x \end{gathered}$ $x\approx15.059$

Hence, you can conclude that the answer is: Second option.

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11 months ago

The ratio of students to adults on a field trip is 8 to 1. Which table correctly shows this ratio for each grade?

iogann1982 [59]

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2 years ago

A cooler contains fifteen bottles of sports drink: eight lemon-lime flavored and seven orange flavored

dem82 [27]

Answer:

Mutually exclusive,

$P(\text{Lemon-lime or orange})=\frac{2}{3}$

Step-by-step explanation:

Please consider the complete question:

Determine if the scenario involves mutually exclusive or overlapping events. Then find the probability.

A cooler contains twelve bottles of sports drink: four lemon-lime flavored, four orange flavored, and four fruit-punch flavored. You randomly grab a bottle. It is a lemon-lime or an orange.

Let us find probability of finding one lemon lime drink.

$P(\text{Lemon-lime})=\frac{\text{Number of lemon lime drinks}}{\text{Total drinks}}$

$P(\text{Lemon-lime})=\frac{4}{12}$

$P(\text{Lemon-lime})=\frac{1}{3}$

Let us find probability of finding one orange drink.

$P(\text{Orange})=\frac{\text{Number of orange drinks}}{\text{Total drinks}}$

$P(\text{Orange})=\frac{4}{12}$

$P(\text{Orange})=\frac{1}{3}$

Since probability of choosing a lemon lime doesn't effect probability of choosing orange drink, therefore, both events are mutually exclusive.

We know that probability of two mutually exclusive events is equal to the sum of both probabilities.

$P(\text{Lemon-lime or orange})=P(\text{Lemon-lime})+P(\text{Orange})$

$P(\text{Lemon-lime or orange})=\frac{1}{3}+\frac{1}{3}$

$P(\text{Lemon-lime or orange})=\frac{1+1}{3}$

$P(\text{Lemon-lime or orange})=\frac{2}{3}$

Therefore, the probability of choosing a lemon lime or orange is $\frac{2}{3}$ .

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2 years ago