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Olegator [25]
2 years ago
6

The repair shop owner feels that he is losing many customers needing routine repair because of the long wait. He dedicates one h

oist for routine repair and one for major repairs. A study indicates that routine repairs are processed at the rate of 3 per hour and major repairs at the rate of 1 per hour. There are now 5 people waiting on average for routine repairs and 3 waiting on average for major repairs
Business
1 answer:
a_sh-v [17]2 years ago
6 0

Answer:

This question highlight regarding finding out the Flow time which were given as - Inventory / Time.

The repair shop is now dedicates that one elevator for routine and one for key. Now compute the Flow time for both cases.

Case 1: - For Routine Repairs: -

Inventory = 5

Time = 3 per hour.

Therefore, the Flow Time = Inventory / Time = 5/3 = 1.67 hours

Thus, the cars wait time at an average of 1.67 hrs. before being served at routine repairs.

Case 2: - For Major Repairs: -

Inventory = 3

Time = 1 per hour.

Therefore, Flow Time = Inventory / Time = 3/1 = 3 hours

Thus, the cars wait time at an average of 3 hrs. before being served at major repairs.

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Jan. 1:

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