Hot dogs and hot dog buns are complements. if the price of a hot dog falls, then

2 answers:

7 0

Then the price of hot dog buns would go up, I assume.
If you were the owner of the leading hot dog bun company, and hot dog prices went down, then more people would need to buy hot dog buns. So if you wanted to profit from that you'd raise your prices a little bit to make more money.

SIZIF [17.4K]3 years ago

6 0

Then a lot more people should buy more hot dogs

You might be interested in

Which of these graphs represents a rate of change of 4?

mamaluj [8]

<h2><em>The last graph because the slope is 40. </em></h2><h2><em> </em></h2><h2><em>Slope equals rise over run </em></h2><h2><em> </em></h2><h2><em>Rise is 4/ Run is 1 </em></h2><h2><em> </em></h2><h2><em>4/1=4 </em></h2><h2><em> </em></h2><h2><em>Slope (rate of change)=4</em></h2><h2><u><em>C</em></u></h2>

7 0

2 years ago

find a function whose second derivative is y''=12x-2 at each point (x,y) on its graph and y=-x+5 is tangent to the graph at the

pogonyaev

Start by integrating y'' twice to get function y(x).

$y' = \int (12x - 2) dx = 6x^2 -2x + c \\ \\ y = \int (6x^2 -2x+c )dx= 2x^3-x^2 +cx+d$

Next find value of coefficients 'c' and 'd' using the given tangent line
The slope of tangent line is equal to y' when x=1.

$6x^2 -2x+c = -1, x = 1 \\ \\ 6-2+c = -1 \\ \\ c = -5$

The tangent line intersects the curve y(x) when x = 1.
If x = 1, then y = 4 (From y =-x+5)

$y = 2x^3 -x^2-5x +d , x = 1, y = 4 \\ \\ 2-1-5+d = 4 \\ \\ d = 8$

Final Answer:
$y = 2x^3 -x^2 -5x+8$

3 0

3 years ago

Susan is 4 years older than kylie. Paige is one less than four times Kylies age. The combined age of the three girls is 33. How

Zina [86]

Kylie is 5, Susan is 9, and Paige is 19

5 0

3 years ago

Read 2 more answers

Write a function g whose graph represents a reflection in the y-axis of the graph of f(x)=−3+|x−11|.

Jet001 [13]

The function g whose graph represents a reflection in the y-axis of the graph of f(x)=−3+|x−11| is; g(x) = x + 8

<h3>How to solve transformation problems?</h3>