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Sveta_85 [38]
3 years ago
9

DUE IN 30 MINTUES!!!!!PLEASEEE HELP!!!

Mathematics
1 answer:
marusya05 [52]3 years ago
4 0
7 Oxen= $280
2,150 Ibs of food= $430
15 clothes= $150
430+280+150=860
Tax- 860 x 1.09= $937.4

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Please help helpppppp
Deffense [45]
Your hand looks nice... 

Anyway, 11/4 is the answer


5 0
3 years ago
–3x – 3 < –63 This is rlly needed.
NISA [10]
-3x -3 < -63 subtract the 3 first
-3x < -60 then divide the -3 from both sides
x < 20 is your answer
6 0
3 years ago
The coordinate grid shows W,X,Y,Z <br><br> which point is best represented by ordered pair (-3,2.5)
vlabodo [156]

Answer:

ㅎ료 혼혈 메이크업

Step-by-step explanation:

호호 불면서 날씨가 너무 많은 관심 부탁드립니다な屋根やさやかMUGEN Falken

Mazda rx7 veilside Acura NSX Honda integra type r Lamborghini huracan

8 0
3 years ago
The mean points obtained in an aptitude examination is 159 points with a standard deviation of 13 points. What is the probabilit
Korolek [52]

Answer:

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 159, \sigma = 13, n = 60, s = \frac{13}{\sqrt{60}} = 1.68

What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?

This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So

X = 160

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 159}{1.68}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 150

Z = \frac{X - \mu}{s}

Z = \frac{158 - 159}{1.68}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

7 0
3 years ago
The sum of two non-zero numbers a and b equals the sum of their reciprocals. If a+b≠0, what is the product of the two numbers?
Vadim26 [7]

Answer:

ab = 1

Step-by-step explanation:

A Reciprocal of a number is a number which when multiplied by the original number yields the multiplicative number, 1.

So the reciprocal of x would be x⁻¹ or ¹⁄ₓ

The information we are given states that the sum of the two non-zero numbers a and b equals the sum of their reciprocals.

So we can write this into an equation and solve,

(See image)

Once we solve, we get the equation (ab-1)(a+b) = 0

We are given info that a+b≠0

So for the above equation to be true, ab-1 has to equal 0

For <em>this</em> to be true, the product ab must equal 1

7 0
3 years ago
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