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Cerrena [4.2K]
3 years ago
5

Using the prostate data from the faraway package with lpsa (log prostate specific antigen) as response and lcavol (log cancer vo

lume) as predictor, the fitted model is lpsa = 1.507 + 0.719 lcavol. Provide an interpretation of the estimated coefficient for lcavol based on the fact that both variables are log-transformed.

Mathematics
1 answer:
rewona [7]3 years ago
8 0

Answer:

Step-by-step explanation:

Given that,pros.

lpsa = 1.507 + 0.719 lcavol

lpsa=0.719 lcavol + 1.507

Comparing this to equation of a straight line, y=mx+c

Then,

slope (m) = 0.719

And intercept (c) on y axis is 1.507

Then, the x axis is lcavol

Also, the y axis is lpsa.

Then the linear model preview is

Check attachment for the preview.

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Assoli18 [71]

Answer:

9x+4x^2-5y

Step-by-step explanation:

Hi there!

Length of the field: 14x-3x^2+2y units

Width of the field: 5x-7x^2+7y units

To find how much greater the length of the field is than the width, subtract the width from the length:

14x-3x^2+2y-(5x-7x^2+7y)

Open up the parentheses

= 14x-3x^2+2y-5x+7x^2-7y

Combine like terms

= 14x-5x-3x^2+7x^2+2y-7y\\= 9x+4x^2-5y

Therefore, the length is 9x+4x^2-5y units greater than the width.

I hope this helps!

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Answer: £164.50

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Step-by-step explanation:

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