Answer:
probably 2 or 4
Step-by-step explanation:
Just plot the values onto a normal number line
Answer:
the last one if I'm correct
Step-by-step explanation:
but im not sure I always second guess
Answer:
1,404,000 unique passwords are possible.
Step-by-step explanation:
The order in which the letters and the digits are is important(AB is a different password than BA), which means that the permutations formula is used to solve this question.
Permutations formula:
The number of possible permutations of x elements from a set of n elements is given by the following formula:

In this question:
2 digits from a set of 10(there are 10 possible digits, 0-9).
3 characters from a set of 26. So

1,404,000 unique passwords are possible.
Question 1 demonstrates the Commutative Property.