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3 years ago

What is 38.25 rounded to the correct significant digits?

Mathematics

2 answers:

Dafna1 [17]3 years ago

6 0

Answer:

significant of number 38.25 will be:

number 38.25 has 4 significant figure.

converting into in 3 significant figure we have to round off this number 38.25 to get 38.3 which have 3 significant figure.

converting into in 2 significant figure rounding off number 38.25 we get 38 which have 2 significant figure.

converting into in 1 significant figure converting number to 40 which have 1 significant figure.

tamaranim1 [39]3 years ago

3 0

Rounded off to one significant digit; 40

Rounded off to two significant digits; 38

Rounded off to three significant digits; 38.3

Hope this helped! :)

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kolezko [41]

The <em>algebraic</em> expression $x^{10/3}$ is equivalent to the <em>algebraic</em> expression $x^{3}\cdot \sqrt[3]{x}$ . Thus, the right choice is option D.

<h3>How to apply power and root properties to rewrite a given expression</h3>

In this question we must apply the following set of <em>algebraic</em> properties to simplify a given expression:

$x^{m/n} = \sqrt[n]{x^{m}} = \left(\sqrt[n]{x}\right)^{m}$ (1)

$x^{m+n} = x^{m}\cdot x^{n}$ (2)

$x^{m\cdot n} = \left(x^{m}\right)^{n} = \left(x^{n}\right)^{m}$ (3)

Where:

<em>m</em>, <em>n</em> - Exponents
<em>x</em> - Base

And also by apply the definition of power.

If we know that the given expression is $x^{10/3}$ , then the equivalent expression is:

$x^{10/3} = \sqrt[3]{x^{10}} = \sqrt[3]{x^{9}\cdot x} = \sqrt[3]{x^{9}}\cdot \sqrt[3]{x} = x^{3}\cdot \sqrt[3]{x}$

The <em>algebraic</em> expression $x^{10/3}$ is equivalent to the <em>algebraic</em> expression $x^{3}\cdot \sqrt[3]{x}$ . Thus, the right choice is option D.

To learn more on roots, we kindly invite to check this verified question: brainly.com/question/1527773

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<h3>Hope it is helpful...</h3>

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