The English alphabet contains 26 letters (a, b, c, ...y, z).
The digits from 0 to 9 are a total of 10.
A keycode contains 2 letters, and 3 numbers, for example:
AB 598; MM 139; NT 498; ...
So there are 26 possible choices for the first letter, which can combined with any of the 26 possible choices for the second letter, so there are a total of
26*26=676 possible pairs of letters.
Similarly, the 10 possible choices for the first number, which can be combined with the 10 possible choices for the second number, and the 10 possible choices for the third number make a total of :
10*10*10=1,000 possible triples of numbers.
Any of the 676 possible pairs of letters can be combined with any of the possible 1,000 triples of numbers. This makes a total of
676*1,000=676,000 keycodes.
Answer: 676,000
Answer:
Sorry I don't talk uwu voice I don't no wat to speak uwuuu I just yry one
Answer:
Male=21 Female=14
Step-by-step explanation:
So the problem would be (f)+(f+7)=35
first you would subtract 7 from 35
Now you have (f)+(f)=28 or 2f=28
Then you divide both sides by two
f=14
and since we know there is 7 more males then the answer is
m=21
Answer:
Well, in reality, all circles are similar to each other. They will all have the same angles, and they don't really have side lengths. So, they are similar.
But to PROVE they are similar, we will transform Circle C to match circle E.
Circle C has a center at (-3, 1), and Circle E has a center of (4, 9). For Circle C to have the same center as Circle E, we will translate Circle C 7 units to the right, and 8 units up.
Since Circle C has a radius of 4, and Circle E has a radius of 3, dilate Circle C by a factor of 3/4. That way, the radius is 3 units as well.
And there you go! The two circles will map perfectly on top of each other.
Hope this helps!
Simplify : 30 – 5(15 - 10).
Apply BODMAS :
B- Brackets
O-Of
D-Division
M-Multiplication
A-Adition
S-Subtraction
Answer : D) 5
