If the p-value is smaller than the level of significance, then it indicates strong evidence against the null hypothesis, as there is less than a 5% probability the null hypothesis is correct.
In this question,
A p-value is a probability, calculated after running a statistical test on data and it lies between 0 and 1. The p-value only tells you how likely the data you have observed is occurred under the null hypothesis.
One of the most commonly used p-value is 0.05. If the value is greater than 0.05, the null hypothesis is considered to be true. If the calculated p-value turns out to be less than 0.05, the null hypothesis is considered to be false, or nullified (hence the name null hypothesis).
A small p-value (< 0.05 in general) means that the observed results are unusual, assuming that they were due to chance only. Now, the smaller the p-value, the stronger the evidence that should reject the null hypothesis.
Hence we can conclude that if the p-value is smaller than the level of significance, then it indicates strong evidence against the null hypothesis, as there is less than a 5% probability the null hypothesis is correct.
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In mathematics, the statement if a, then b, says that if a is true, then be is true. If you think about it, this makes sense too. That means that the answer is C., because of the definition of the statement.
First subtract the x variable on both sides so on the first equation youll have -6y=8x+60 then divide 6 on all variables which means youll have y=8/6x+10 and in the second equation you do the same thing and youll have y=-5/6x-11.5
Answer:
They both involve writing a rate.
Step-by-step explanation:
EDGENUITY ANSWER
Answer:
![\log_{10}(147) = 2.1673](https://tex.z-dn.net/?f=%5Clog_%7B10%7D%28147%29%20%3D%202.1673)
Step-by-step explanation:
Given
![\log_{10} 3 = 0.4771](https://tex.z-dn.net/?f=%5Clog_%7B10%7D%203%20%3D%200.4771)
![\log_{10} 5 = 0.6990](https://tex.z-dn.net/?f=%5Clog_%7B10%7D%205%20%3D%200.6990)
![\log_{10} 7= 0.8451](https://tex.z-dn.net/?f=%5Clog_%7B10%7D%207%3D%200.8451)
![\log_{10} 11 = 1.0414](https://tex.z-dn.net/?f=%5Clog_%7B10%7D%2011%20%3D%201.0414)
Required
Evaluate ![\log_{10}(147)](https://tex.z-dn.net/?f=%5Clog_%7B10%7D%28147%29)
Expand
![\log_{10}(147) = \log_{10}(49 * 3)](https://tex.z-dn.net/?f=%5Clog_%7B10%7D%28147%29%20%3D%20%5Clog_%7B10%7D%2849%20%2A%203%29)
Further expand
![\log_{10}(147) = \log_{10}(7 * 7 * 3)](https://tex.z-dn.net/?f=%5Clog_%7B10%7D%28147%29%20%3D%20%5Clog_%7B10%7D%287%20%2A%207%20%2A%203%29)
Apply product rule of logarithm
![\log_{10}(147) = \log_{10}(7) + \log_{10}(7) + \log_{10}(3)](https://tex.z-dn.net/?f=%5Clog_%7B10%7D%28147%29%20%3D%20%5Clog_%7B10%7D%287%29%20%2B%20%5Clog_%7B10%7D%287%29%20%2B%20%5Clog_%7B10%7D%283%29)
Substitute values for log(7) and log(3)
![\log_{10}(147) = 0.8451 + 0.8451 + 0.4771](https://tex.z-dn.net/?f=%5Clog_%7B10%7D%28147%29%20%3D%200.8451%20%2B%200.8451%20%2B%200.4771)
![\log_{10}(147) = 2.1673](https://tex.z-dn.net/?f=%5Clog_%7B10%7D%28147%29%20%3D%202.1673)