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3 years ago

-12,60,-300,1500 what are the next two number s

Mathematics

2 answers:

VikaD [51]3 years ago

4 0

Answer:

- 7500, 37500

Step-by-step explanation:

Note the common ratio r between consecutive terms of the sequence, that is

r = 60 ÷ - 12 = - 300 ÷ 60 = 1500 ÷ - 300 = - 5

This indicates that the sequence is geometric with r = - 5

To obtain the next term in the sequence multiply the previous term by - 5

1500 × - 5 = - 7500

- 7500 × - 5 = 37500

larisa86 [58]3 years ago

3 0

Answer:-7500, 37,500

Step-by-step explanation:

The patter is multiply by negative 5 -12*5=60, 60*-5=-300... so 1500* -5=-7500, and -7500*-5=37,500

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The box plot shows the undergraduate in-state tuition per credit hour at four-year public colleges. 0 300 600 900 1,200 $1,500 a

kkurt [141]

Answer:

(a) The median estimate is 450.

(b) The first and third quartiles are 300 and 750 respectively.

(c) The interquartile range is 450.

(d) The particular value which is less than 150 or it is more than 1200, is considered as an outlier.

(e) Yes, there is one outlier in our data which is the value of 1,500.

(f) The distribution is positively skewed.

Step-by-step explanation:

We are given that the box plot shows the undergraduate in-state tuition per credit hour at four-year public colleges. 0, 300, 600, 900, 1,200, 1,500.

(a) As we can see in the box plot that the middlemost data lies between 300 and 600, that means;

Median is given by the average of the two numbers, i.e;

Median = $\frac{300+600}{2}$

= $\frac{900}{2}$ = 450

So, the median estimate is 450.

(b) As we know that the first quartile represents 25% of the data values and the third quartile represents 75% of the data values.

So, from the box plot given; we can observe that the first quartile, $Q_1$ = 300 and the third quartile lies between the values of 600 and 900, i.e;

Third quartile, $Q_3$ = $\frac{600+900}{2}$

= $\frac{1500}{2}$ = 750

So, the first and third quartiles are 300 and 750 respectively.

(c) The interquartile range is given by the following formula;

Interquartile range = Third quartile - First quartile

= $Q_3-Q_1$

= 750 - 300 = 450

(d) From the box plot; it is clear that if the particular value is less than 150 or it is more than 1200, then it is considered as an outlier.

(e) Yes, there is one outlier in our data which is the value of 1,500.

(f) The distribution is positively skewed because the more values are on the right side of the curve and it skewed towards the right.

4 0

4 years ago

Rosemary put 7 dimes and 3 pennies any tip chart the cafe this show this amount as a decimal and as a fraction home much more ch

elena55 [62]

Answer:

Penny:

3/100 ; 0.03

Dimes :

7/10 ; 0.7

Amount to add to make whole number = $0.23

Step-by-step explanation:

Recall:

100 pennies = $1

1 penny = 1 / 100

3 Pennies = 3 / 100 (In fraction)

3 pennies = 0.03

10 dime = $1

1 dime = 10 /100 = 1/ 10

7 dimes = 7/10 (fraction)

7 dimes = 0.7

To make the money in jar a whole dollar :

Amount to be added :

1 - (0.03 + 0.70)

1 - 0.73

= $0.27

6 0

3 years ago

Type a digit that makes this statement true.<br><br> 425,9<br> 0 is divisible by 3.

disa [49]

Answer:

1, 4, or 7

Step-by-step explanation:

For 425,9__0 to be divisible by three, the sum of the digits must be a multiple of three.

Using this knowledge, the numbers 1, 4, and 7 are all answers to this problem.

425, 910: 4 + 2 + 5 + 9 + 1 + 0 = 21

21 is divisible by 3.

Repeat this for 4 and 7.

Hope this helped!

3 0

2 years ago

Read 2 more answers

Jacob went to the gas station with 17.70 he brought a drink for 2.90 and he wanted to spend the rest of the money and a bag of c

nikdorinn [45]

Answer:

17.70-2.90=14.80

14.80/1.85=8

He could buy a maximum of 8 chip bags.

bags of chips = x

17.70-2.90/1.85≥x

4 0

3 years ago

The graph of a function

Alex17521 [72]

Note main properties of $\dfrac{dy}{dx}$ and $\dfrac{d^2y}{dx^2}:$

1. $\dfrac{dy}{dx}:$

if $\dfrac{dy}{dx}>0,$ the function is increasing;
if $\dfrac{dy}{dx}$ the function is decreasing;
if $\dfrac{dy}{dx}=0,$ the function can have minimum or maximum.

2. $\dfrac{d^2y}{dx^2}:$

if $\dfrac{d^2y}{dx^2}>0,$ the function is concave up;
if $\dfrac{d^2y}{dx^2}$ the function is concave down;
if $\dfrac{d^2y}{dx^2}=0,$ the function can have inflection point.

Now consider all options:

1. If $\dfrac{dy}{dx}>0,$ $\dfrac{d^2y}{dx^2}>0,$ then you should pick point B.

2. If $\dfrac{dy}{dx}$ $\dfrac{d^2y}{dx^2}$ then you should pick point E.

3. If $\dfrac{dy}{dx}$ $\dfrac{d^2y}{dx^2}>0,$ then you should pick point A.

Note that

at point C $\dfrac{dy}{dx}>0,$ $\dfrac{d^2y}{dx^2}$
at point D $\dfrac{dy}{dx}=0,$ $\dfrac{d^2y}{dx^2}$

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4 years ago

Read 2 more answers