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Maslowich
3 years ago
11

The children became Americanized much faster than their parents. Often this caused painful conflicts in immigrant families. A ga

p appeared between the children and their parents. The parents clung to Old World customs and beliefs. The kids spoke English all day with their friends. They thought in American terms. More than anything else, they wanted to be accepted as equals in their adopted land.
Which other detail best supports the idea that children became comfortable in America more quickly than their parents?

When they left school, they looked, talked, and acted just like other American kids.
During hard times, kids had to drop out of school early. In the days before World War I, it was an accomplishment to finish grammar school.
Many kids went directly from grammar school to special vocational schools sponsored by private agencies. . . .
Students were also instructed in the fundamentals of health, hygiene, and personal grooming.
Mathematics
1 answer:
Goshia [24]3 years ago
8 0

The right answer is <u>Many kids went directly from grammar school to special vocational schools sponsored by private agencies. . .</u>

I hope it helps :)

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F(x) = x2 + 1 g(x) = 5 – x (f + g)(x) =
nordsb [41]

Answer:

x^3 - x^2 - 6x

Step-by-step explanation:

First, add f +g

x^2 + 1 + 5 -x (combine like terms)

x^2 - x +6  

Next, multiply the new equation by x

x(x^2 - x + 6)    Use distributive property

= x^3 - x^2 + 6x

5 0
3 years ago
Marianna went running and had 16 of a bottle of water left when she stopped to rest. She went to a water fountain and filled it
vovikov84 [41]

Answer:

7/100

Step-by-step explanation:

16/100 to 23/100

23-16 = 7

7/100 added

4 0
2 years ago
Zoologists are studying two newly discovered species of insects in a previously unexplored section of rain forest. They estimate
salantis [7]
The population Pa of insect A after t years is given by the equation 
     Pa = 1.3(1-0.038)^t 
while the population Pb of insect B after t years is 
     Pb = 2.1(1-0.046)^t

We equate the above expressions to find the number of years t it will take the two populations to be equal: 
     Pa = Pb
     1.3(1-0.038)^t  = 2.1(1-0.046)^t
     1.3(0.962)^t  = 2.1(0.954)^t
These are the equations that can be used to determine how long it will be before the populations of the two species are equal.

We can now solve for t:
     (0.962)^t / (0.954)^t = 2.1/1.3
     (0.962/0.954)^t = 2.1/1.3
After taking the log of both sides of our equation, number of years t is
     t = log (2.1/1.3) / log (0.962/0.954)
     t = 57 years
Therefore, it will take 57 years for the population of insect A to equal the population of insect B.
8 0
3 years ago
Read 2 more answers
A star is a swirling mass of dense gases powered by thermonuclear reactions. The great solar furnace transforms 7 million tons o
marta [7]

Answer:

2.20752 x 10^{24}

Step-by-step explanation:

The first thing you have to do is to look for the number of seconds in one year. You have to multiply 365 days by 86,400 seconds.

  • 365 days refer to the total number of days per year
  • 86,400 seconds refer to the number of seconds per day

Let's solve.

  • 365 x 86,400 = 31,536,000 or 3.1536 x 10^{7}

<em>Therefore, one year has 3.1536 x </em>10^{7}<em> seconds.</em>

Next, you have to know the number of seconds in 10 billion years.

  • (3.1536 x 10^{7}) x  (1.0 x 10^{10}) = 3.1536 x 10^{17}

The last step is to multiply the number of seconds in 10 billion years to 7 million tons of mass per second.

  • (3.1536 x 10^{17}) x 7,000,000 = 2.20752 x 10^{24}
6 0
2 years ago
Find the area of a parallelogram with bass 15 yards and height 21 2/3yards
r-ruslan [8.4K]
Convert the mixed number <span>21 <span>2/3</span></span><span> into an </span><span>improper fraction.
</span>15⋅<span>65/3

</span><span>Cancel 3 and 15.
</span><span>5⋅65

</span>Multiply 5<span> by </span>65<span> to get </span><span>325.
</span>325

Answer:
325
4 0
3 years ago
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