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erik [133]
3 years ago
10

Given the quadratic equation below, determine which situation it could represent? x2 -4x = 60

Mathematics
1 answer:
yarga [219]3 years ago
4 0

Answer:

The solution is x = 10 and x = -6. This quadratic could be represented in factored form as (x - 10)(x + 6) or on a graph with x-intercepts at (10,0) and (-6,0).

Step-by-step explanation:

To solve the quadratic, write the quadratic in standard form and factor the equation.

x² - 4x = 60

x² - 4x - 60 = 0

(x - 10)(x + 6) = 0

x = 10 and x = -6

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61.7 is what percent of 64? Round to the nearest thousandth.
scoundrel [369]

Answer:

96.406%

Step-by-step explanation:

(61.7 ÷ 64) x 100 = 96.40625 = 96.406% (nearest hundredth)

8 0
2 years ago
Why do translations produce parallel lines
pav-90 [236]

Answer:The distance between the lines stays constant, and they never intersect. In other words, you can translate (move) either line by that constant distance, in some direction, to get the other line. It's just like how when you change the y-intercept but keep the slope the same, you get parallel lines.

Step-by-step explanation:

Hope this helps ツ

7 0
3 years ago
The number of people arriving for treatment at an emergency room can be modeled by aPoisson process with a rate parameter of 5/h
saveliy_v [14]

Answer:

(a) The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour is 0.7350.

(c) The expected arrivals in a 45 minute period (0.75 hours) is 3.75 arrivals.

Step-by-step explanation:

(a) If the arrivals can be modeled by a Poisson process, with λ = 5/hr, the probability of having exactly four arrivals during a particular hour is:

P(X=4)=\frac{\lambda^{X}*e^{-\lambda}  }{X!} =\frac{5^{4}*e^{-5}  }{4!}=\frac{625*0.006737947}{24} =\frac{4.211}{24}=0.1754

The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour can be written as

P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))

Using

P(X)=\frac{\lambda^{X}*e^{-\lambda}  }{X!}

We get

P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))\\P(X>3)=1-(0.0067+ 0.0337+ 0.0842 + 0.1404 )\\P(X>3)=1-0.2650=0.7350\\

The probability that at least 3 people arriving during a particular hour is 0.7350.

(c) The expected arrivals in a 45 minute period (0.75 hours) is

EV=\lambda*t=5*0.75=3.75

8 0
3 years ago
I need help with this one please
skelet666 [1.2K]

Answer:

perimeter of figure = 24.28

Step-by-step explanation:

semicircle ' s perimeter = π r = 3.14 × 2 = 6.28 cm

perimeter of 3 sides of parallelogram = 7 +7+4= 18 cm.

perimeter of figure = 18 +6.28 = 24.28

approx value = 24.30 cm

3 0
2 years ago
Please answer it! it’s for a test please I’ll give branliest!!
vova2212 [387]

Answer:

what there is nothing there

7 0
2 years ago
Read 2 more answers
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