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Usimov [2.4K]
3 years ago
8

two variables are negatively associated​ if, whenever the value of one variable​ increases, the value of the other variable decr

eases. Will the following variables have positive​ correlation, negative​ correlation, or no​ correlation?
Mathematics
1 answer:
Flura [38]3 years ago
6 0

Answer:

The correct answer is: Negative correlation.

Step-by-step explanation:

The negative correlation determines the relationship between two variables, it says that there is an inverse relationship between two variables, whenever one of them is decreasing, the other one increases, and it's the same in reverse.

You might be interested in
Use the Distributive Property to write each expression as an equivalent algebraic expression.
Romashka [77]

Answer:

9x - 45

Step-by-step explanation:

To simplify this expression, we need to use Distributive Property to get rid of the parentheses. So, we multiply the -9 by everything inside the parentheses.

-9(-x + 5)

-9 · -x = 9x

-9 · 5 = -45

Now we add our products together.

9x + -45

Since there is a '+' sign and a '-' sign next to each other, we can simplify it to just a '-'.

9x - 45

Hope this helped! Let me know if you have any other questions! :)

6 0
3 years ago
Read 2 more answers
I need help with this please I am very tired and need someone to do this ONE question to help if you can that will be great!
irina [24]

Answer:

462 cu. in

Step-by-step explanation:

See attached formula

4 0
3 years ago
If you roll a number cube 22 times about how many times do you expect to roll a numeber Less than 4?
frozen [14]

Answer:

About 7 times

Step-by-step explanation:

8 0
3 years ago
Which equation is related to √x+10-1=x ? The square root is over the x+10
Sergio [31]

Answer:

  (b)  x + 10 = x^2 + 2x + 1

Step-by-step explanation:

The equation can be transformed to one without the radical by isolating the radical and squaring both sides.

__

  \sqrt{x+10}-1=x\qquad\text{given}\\\\\sqrt{x+10}=x+1\qquad\text{add 1 to both sides}\\\\x+10=(x+1)^2\qquad\text{square both sides}\\\\\boxed{x+10=x^2+2x+1}\qquad\text{eliminate parentheses}

_____

<em>Additional comment</em>

In typeset formulas, radicals, fraction bars, and superscript formatting serve to group expressions. In plain text, the only available grouping symbol is parentheses.

  \sqrt{x+1}}\ \Rightarrow √(x+1)

3 0
2 years ago
Can someone please help I really need these points
spayn [35]

Given:

Two chords intersect each other inside the circle.

To find:

The value of x.

Solution:

According to intersecting chords theorem, if two chords intersect each other inside the circle, then the product of two segments of one chord is equal to  the product of two segments of second chord.

In the given circle,

AE\times CE=BE\times DE

(3x-11)\times (5x-4)=(x+2)\times (-x+17)

15x^2-12x-55x+44=-x^2+17x-2x+34

15x^2-67x+44+x^2-15x-34=0

16x^2-82x+10=0

Divide both sides by 2.

8x^2-41x+5=0

Splitting the middle term, we get

8x^2-40x-x+5=0

8x(x-5)-1(x-5)=0

(8x-1)(x-5)=0

Using zero product property, we get

(8x-1)=0 or (x-5)=0

x=\dfrac{1}{8} or x=5

For x=\dfrac{1}{8}, the side AE is negative. So, x=\dfrac{1}{8} is not possible.

Therefore, the required solution is x=5.

6 0
3 years ago
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