A) N +2 = Q which equals
A) N -Q = -2
B) .05N +.25Q = 3.50 multiplying A) by .25
A) .25N -.25Q = -.5 then adding A) and B)
.30N = 3
Nickels = 10 Quarters = 12
*************DOUBLE CHECK ***************
.05 nickels = $0.50 .25 Quarters = $3.00
Answer:
There are two choices for angle Y: 
for 
, 
for 
.
Step-by-step explanation:
There are mistakes in the statement, correct form is now described:
<em>In triangle XYZ, measure of angle X = 49°, XY = 18 and YZ = 14. Find the measure of angle Y:</em>
The line segment XY is opposite to angle Z and the line segment YZ is opposite to angle X. We can determine the length of the line segment XZ by the Law of Cosine:
(1)
If we know that 
, 
and 
, then we have the following second order polynomial:
(2)
By the Quadratic Formula we have the following result:
There are two possible triangles, we can determine the value of angle Y for each by the Law of Cosine again:
1)
![Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-15.193^{2}}{2\cdot (18)\cdot (14)} \right]](https://tex.z-dn.net/?f=Y%20%3D%20%5Ccos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B18%5E%7B2%7D%2B14%5E%7B2%7D-15.193%5E%7B2%7D%7D%7B2%5Ccdot%20%2818%29%5Ccdot%20%2814%29%7D%20%5Cright%5D)
2)
![Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-8.424^{2}}{2\cdot (18)\cdot (14)} \right]](https://tex.z-dn.net/?f=Y%20%3D%20%5Ccos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B18%5E%7B2%7D%2B14%5E%7B2%7D-8.424%5E%7B2%7D%7D%7B2%5Ccdot%20%2818%29%5Ccdot%20%2814%29%7D%20%5Cright%5D)
There are two choices for angle Y: for , for .
Step 1: 0.282 = 282⁄1000
Step 2: Simplify 282⁄1000= 141⁄500
Angles a, b, and c are all 60°. A triangle’s angles add up to 180, and if the triangle is equilateral, each angle must be 60 (180/3). Angle d is 120° because b and d form a supplementary angle (180°), so 180-60 is 120. Angle e and f and 30°. Angles c and e form complementary angles (90°), so 90-60=30. For f, if the triangle adds up to 180, 180-120-30 = f. The 120 comes from d and the 30 comes from e. This leaves f as 30.
