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Phantasy [73]
3 years ago
14

6M + 1= -23 SOLVE THE EQUATION

Mathematics
1 answer:
Inessa05 [86]3 years ago
5 0
6m + 1= -23 \\ \\ 6m = -23 - 1 \\ \\ 6m = -24 \\ \\ m = - \frac{24}{6} \\ \\ m = -4 \\ \\

The final result is: m = -4.
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Do side lengths 8,7 and 15 create a triangle ?
dexar [7]

Answer:

Yes

Step-by-step explanation:

To make a triangle the 2 smaller sides must join together to become greater than or equal to the biggest side.

8+7=15

<em>Therefore,</em>

<em>side lengths 8, 7, and 15 do create a triangle.</em>

<em />

<em>Hope this helps </em>

3 0
4 years ago
Read 2 more answers
Use the identity (x^2+y^2)^2=(x^2−y^2)^2+(2xy)^2 to determine the sum of the squares of two numbers if the difference of the squ
marissa [1.9K]

Answer:

Step-by-step explanation:

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2

Adding and substracting 2x^2y^2

We get

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2 +2x^2y^2-2x^2y^2

And we know a^2-2ab+b^2=(a-b)^2

So we identify (x^2)^2 as a^2 ,(y^2)^2 as b^2 and -2x^2y^2 as - 2ab. So we can rewrite (x^2+y^2)^2=(x^2 - y^2)^2 + 2x^2y^2 + 2x^2y^2= (x^2 - y^2)^2+4x^2y^2= (x^2 - y^2)^2+2^2x^2y^2

Moreever we know (a·b·c)^2=a^2·b^2·c^2 than means 2^2x^2y^2=(2x·y)^2

And (x^2+y^2)^2=(x^2 - y^2)^2 + (2x·y)^2

5 0
4 years ago
Factor the polynomial. 48w^7 30w^4 a) 6w^4(8w^3 5) b) 6w^3(8w^4 5w) c) w^4(48w^3 30) d) 6(8w^7 5w^4)
Oliga [24]
48w^7 + 30w^4 = 6w^4(8w^3 + 5)
8 0
3 years ago
Does anyone know what the 5√2 (simplify radicals)?
maks197457 [2]

Answer:

  5√2 is as simple as it gets

  5√2 ≈ 7.071068

Step-by-step explanation:

One simplifies radical expressions by removing from under the radical any squares that might be there. 2 is a prime number, so has no square factors. The simplest form of this radical expression is the one given:

  5√2

Your calculator can tell you the value of this irrational number is about ...

  5√2 ≈ 7.071068

8 0
4 years ago
X+6=20 so what must X represent to get blank plus 6=20??
Gelneren [198K]

Answer:

14

Step-by-step explanation:

20-6=14

x=14

8 0
3 years ago
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