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kakasveta [241]
2 years ago
7

The area of the small shape is 35 square feet. The big shape is larger by a scale factor of 4/3. Find the area of the large shap

e to the nearest tenth.
a) 62.2 square feet
b) 140 square feet
c) 46.7 square feet
d) 186.7 square feet
e) none of these
Mathematics
1 answer:
sdas [7]2 years ago
4 0

Answer:

Option a) 62.2 square feet  

Step-by-step explanation:

we know that

The dilation is a non-rigid transformation that produces similar figures

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x ----> the area of the large shape

y ----> the area of the small shape

so

z^{2}=\frac{x}{y}

we have

z=\frac{4}{3}

y=35\ ft^2

substitute

(\frac{4}{3})^{2}=\frac{x}{35}

\frac{16}{9}=\frac{x}{35}

solve for x

x=\frac{16}{9}(35)=62.2\ ft^2

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At a movie theatre adult tickets cost $10 and child ticjets cost $6. Which equation can be used to find s, the number of dollars
timurjin [86]

Answer:

s = 10k + 30

Step-by-step explanation:

Cost of Adults ticket = $10 per adult

Cost of Ticket = $6 per child

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Number of Children = 5

s = Total cost

Total cost = (Cost per adult * number of adults) + (Cost per child * Number of children)

s = ($10 * k) + ($6 * 5)

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s = 10k + 30

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2 years ago
HELP PLEASEEEEEEEEEeeeee
maks197457 [2]
Might have to experiment a bit to choose the right answer.

In A, the first term is 456 and the common difference is 10.  Each time we have a new term, the next one is the same except that 10 is added.

Suppose n were 1000.  Then we'd have 456 + (1000)(10) = 10456

In B, the first term is 5 and the common ratio is 3.  From 5 we get 15 by mult. 5 by 3.  Similarly, from 135 we get 405 by mult. 135 by 3.  This is a geom. series with first term 5 and common ratio 3.   a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.

Can you now examine C and D in the same manner, and then choose the greatest final value?  Safe to continue using n = 1000.





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