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kakasveta [241]
3 years ago
7

The area of the small shape is 35 square feet. The big shape is larger by a scale factor of 4/3. Find the area of the large shap

e to the nearest tenth.
a) 62.2 square feet
b) 140 square feet
c) 46.7 square feet
d) 186.7 square feet
e) none of these
Mathematics
1 answer:
sdas [7]3 years ago
4 0

Answer:

Option a) 62.2 square feet  

Step-by-step explanation:

we know that

The dilation is a non-rigid transformation that produces similar figures

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x ----> the area of the large shape

y ----> the area of the small shape

so

z^{2}=\frac{x}{y}

we have

z=\frac{4}{3}

y=35\ ft^2

substitute

(\frac{4}{3})^{2}=\frac{x}{35}

\frac{16}{9}=\frac{x}{35}

solve for x

x=\frac{16}{9}(35)=62.2\ ft^2

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For which value of theta is sin theta equals -1?
Olin [163]

Answer:

The value of Ф is 3π/2

Step-by-step explanation:

* Lets revise the angle Ф in the four quadrant

∵ r = √(x² + y²) ⇒ square the two sides

∴ x² + y² = r²

∵ r = 1

∴ x² + y² = 1

∵ cos² Ф + sin² Ф = 1

∵ x is the adjacent side to Ф and y is the opposite side to Ф

∴ x = cos Ф and y = sin Ф

- At point (1 , 0)

∵ x = 1 , y = 0

∴ cos Ф = 1 and sin Ф = 0

∵ The positive part of x-axis represents the angle 0 and 2π

∴ cos 0 and 2π are 1 and sin 0 and 2π are 0

- At point (0 , 1)

∵ x = 0 , y = 1

∴ cos Ф = 0 and sin Ф = 1

∵ The positive part of y-axis represent the angle π/2

∴ cos π/2 is 0 and sin π/2 is 1

- At point (-1 , 0)

∵ x = -1 , y = 0

∴ cos Ф = -1 and sin Ф = 0

∵ The negative part of x-axis represents the angle π

∴ cos π is -1 and sin π is 0

- At point (0 , -1)

∵ x = 0 , y = -1

∴ cos Ф = 0 and sin Ф = -1

∵ The negative part of y-axis represent the angle 3π/2

∴ cos 3π/2 is 0 and sin 3π/2 is 1

* For the value of Ф = 3π/2 is sin Ф = -1

6 0
3 years ago
Read 2 more answers
How many sequences of 0s and 1s of length 19 are there that begin with a 0, end with a 0, contain no two consecutive 0s, and con
sladkih [1.3K]

65 sequences.

Lets solve the problem,

The last term is 0.

To form the first 18 terms, we must combine the following two sequences:

0-1 and 0-1-1

Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent

So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:

2x + 3y = 18

Case 1: x=9 and y=0

Number of ways to arrange 9 identical 2-term sequences = 1

Case 2: x=6 and y=2

Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28

Case 3: x=3 and y=4

Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35

Case 4: x=0 and y=6

Number of ways to arrange 6 identical 3-term sequences = 1

Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65

Hence the number of sequences are 65.

Learn more about Sequences on:

brainly.com/question/12246947

#SPJ4

8 0
2 years ago
What is the perimeter of triangle with side lengths of 29, 15, and 4xy?
ASHA 777 [7]

Answer:

P =44 + 4xy

Step-by-step explanation:

To find the perimeter of a triangle, add up the three sides

P = 29+15+4xy

P =44 + 4xy

4 0
3 years ago
Please Help ASAP .......
Alekssandra [29.7K]
If it’s asking for Volume then the answer is 226.19.
If it’s surface area then it would be 207.35
5 0
3 years ago
Read 2 more answers
Which of the following is equivalent to<br> (5) 3<br> O 54<br> O 54<br> 05<br> O V5
IrinaK [193]

Answer:

D. \sqrt[3]{5^7}

Step-by-step explanation:

The formula for this conversion is:

a^\frac{x}{n}=\sqrt[n]{a^x}

Substitute the values you currently have.

5^\frac{7}{3}=\sqrt[n]{a^x}

Since we know that

a = 5

x = 7

n = 3

Fill the square root with this.

5^\frac{7}{3}=\sqrt[3]{5^7}

4 0
2 years ago
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