Answer:
If a certain cone with a height of 9 inches has volume V = 3πx2 + 42πx + 147π, what is the cone’s radius r in terms of x?
Step-by-step explanation:
V = 3πx2 + 42πx + 147π
V=3π(x2 + 14x +49)
9.42(x2 + 14x +49)
9.42(x2 + 14x +14) -14 + 49= 0
9.42(x + 7)^2 + 35= 0
9.42(9.42(x + 7)^2 = - 35)9.42
(x + 7)^2 = - 35/9.42)
√(x + 7)^2=√- 35/9.42
x + 7 = - 1.927
x= - 1.927 - 7
x= - 8.927
V = 3π(- 8.927)^2 + 42π(- 8.927) + 147π
V=750.69 - 1177.29 + 461.58
<u>V=34.98</u>
h= 9 inches
V = 13πr2h
34.98 = 13(3.14) (r^2) (h)
34.98 = 40.82 (r^2) 9
34.98 = 367.38 r^2
34.98/ 367.38 = 367.38 r^2/ 367.38
0.095= r^2
I think it is Y equals -1/3x +4.6
Answer:
I have done one question for you
hope it helps
plz Mark as brainlist
Answer:
1 y=-1/10x
2 y=-x-8
3 y= 7/3x or 2 1/3x
Step-by-step explanation:
1 -x=10y
divide -x and 10 by 10
2 y+8=-x
subtract 8
3 -4+7x+4=3y
divide everything by 3
12a + 7(2000) > = 38000
12a + 14000 > = 38000
12a > = 38000 - 14000
12a > = 24000
a > = 24000/12
a > = 2000 <==== at least 2000 alumni would have to buy tickets
