1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
monitta
3 years ago
10

Taylin buys 5 ounces of tea leaves for $2.35. At this rate, how much money does

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
3 0

Answer:

<u>$5.64 </u>

Step-by-step explanation:

to find the solution, first we need to find the rate per oz.  For 5 ounces it is 2.35 so to find the rate per oz we need to find the solution to 2.35/5

2.35/5=.47

tea leaves sell at a rate of 47 per oz

Now to find how many Taylin needs for 12 oz of tea we simply multiply .<em>47</em> by 12

0.47 x 12=5.64

Taylin needs $5.64 to buy 12 ounces of tea leaves

You might be interested in
Use the augmented matrix method to solve the following system of equations. Your answers may be given as decimals or fractions.
Alexandra [31]

Answer:

x\ =\ \dfrac{21}{5}

y\ =\ \dfrac{3}{5}

z = 2

Step-by-step explanation:

Given equations are

x - 2y - z = 2

x + 3y - 2z = 4

-x + 2y + 3z = 2

from the given equations the augmented matrix can be written as

\left[\begin{array}{ccc}1&-2&-1:2\\1&3&-2:4\\-1&2&3:2\end{array}\right]

R_2=>R_2-R_1\ and\ R_3=>R_3+R_1

=\ \left[\begin{array}{ccc}1&-2&-1:2\\0&5&-1:2\\0&0&2:4\end{array}\right]

R_2=>\dfrac{R_2}{5}

=\ \left[\begin{array}{ccc}1&-2&-1:2\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\0&0&2:4\end{array}\right]

R_1=>R_1+2.R_2

=\ \left[\begin{array}{ccc}1&0&-1-\dfrac{2}{5}:2+\dfrac{4}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&2:4\end{array}\right]

=\ \left[\begin{array}{ccc}1&0&\dfrac{-7}{5}:\dfrac{14}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&2:4\end{array}\right]

R_3=>\dfrac{R_3}{2}

=\ \left[\begin{array}{ccc}1&0&\dfrac{-7}{5}:\dfrac{14}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&1:2\end{array}\right]

R_1=>R_1+\dfrac{7}{5}R_3\ and\ R_2+\dfrac{1}{5}R_3

=\ \left[\begin{array}{ccc}1&0&0:\dfrac{14}{5}+\dfrac{7}{5}\\\\0&1&0:\dfrac{2}{5}+\dfrac{1}{5}\\\\0&0&1:2\end{array}\right]

So, from the above augmented matrix, we can write

x\ =\ \dfrac{21}{5}

y\ =\ \dfrac{3}{5}

z = 2

7 0
3 years ago
Pipe A can fill a tank in 40 minutes, while pipe B takes 60 minutes to fill the same tank.
ella [17]

Answer:

24 minutes.

Step-by-step explanation:

This question shows up in a great many places in math or physics, so it is a pretty good question to learn how to do.

First you should note that answer will be under 40 minutes.

1/40 + 1/60 = 1/TimeTotal

The common denominator on the left is 120 minutes

3/40*3 + 2/60*2 = 1/timetotal

3/120 + 2/120      = 1/ timetotal

5/120 = 1/time total  Now to use to the key stop

What you do now is you always turn the left side over. You do the same thing to total time.

120/5 = total time

24 = total time

What this means is that if you let both pipes run for 24 minutes, they will fill the tank working together.

4 0
3 years ago
Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab
Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

<u>Left part:</u>

\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

<u>Right part:</u>

\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

Since simplified left and right parts are the same, then the equality is true.

3 0
3 years ago
All of the expressions that have the same value as LaTeX: 892\div8892 ÷ 8. Group of answer choices LaTeX: 8920\div808920 ÷ 80 La
algol13

Answer:

(a) 8920\div80

(e) 0.892\div0.008

Step-by-step explanation:

Given

892\div8

Required

Select equivalent expression

8920\div80

894\div10

89.2\div0.08

8.92\div0.8

0.892\div0.008

Start  by solving the given expression (using a calculator)

892\div8 = 111.5

Then we solve the given options (using a calculator)

(a) 8920\div80

8920\div80 = 111.5

(b) 894\div10

894\div10 = 89.4

(c) 89.2\div0.08

89.2\div0.08 = 1115

(d) 8.92\div0.8

8.92\div0.8 = 11.15

(e) 0.892\div0.008

0.892\div0.008 = 111.5

The equivalent expressions are (a) and (e)

5 0
2 years ago
What's the solution for (9x + 5) - (4x + 3) ?
Vanyuwa [196]
(9x + 5) - (4x+3) = 0
9x - 4x + 5 - 3 = 0
5x + 2 = 0
5x = -2
5x/5 = -2/5
x= -2/5
5 0
3 years ago
Read 2 more answers
Other questions:
  • What is the value of n in the equation -1.2(2n+4)+6=-9+4(2n+1)
    13·2 answers
  • Help me plz!!!!!!!!!!!!!
    10·1 answer
  • 1<br> COUBT THX<br> 1) Pants regular price $45.69<br> On sale for 25% off.<br> What is the discount?
    7·1 answer
  • Thirty percent of check engine lights turn on after 100,000 miles in a particular model of van. The remainder of vans continue t
    6·2 answers
  • Could i have some help real quick? this is due in an hour and i dont know how to do it
    13·1 answer
  • Help im not good at math lol
    8·2 answers
  • Which one answer fast !
    13·2 answers
  • HELP PLEASE.. ............<br><br>I'm sooooooooooooo bour.....?......​
    10·1 answer
  • 3.) Planet Fitness charges a yearly fee of $50 plus $20 each
    10·1 answer
  • What is the square root of 7<br> i just give the answer to you<br> square root of 7 is 2.64575131
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!