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maw [93]
4 years ago
10

Which equation is in slope intercept form and represents a line with slope 0 through the point (2,3)

Mathematics
2 answers:
Neko [114]4 years ago
4 0
The slope is m = 0 and the line goes through the point (x,y) = (2,3). So x = 2 pairs up with y = 3.

Plug m = 0, x = 2, y = 3 into the equation below. Then solve for b
y = mx+b
3 = 0*2+b
3 = 0+b
3 = b
b = 3

So if m = 0 and b = 3, then
y = mx+b
y = 0*x+3
y = 0+3
y = 3
is the equation of this line. This line is completely horizontal going through points like (0,3), (1,3), (2,3), etc. Every point on this line has a y coordinate of 3. The x coordinate can be any number you want.

Answer: Choice C) y = 3
geniusboy [140]4 years ago
4 0
Any line with slope 0 is horiz.  This particular line is to pass thru (2,3), so the y-intercept, b, is 3.  The equation of the line is then y=3.  x is "silent;" it does not appear in this equation.

You could also write y = 3 as    y = 0(x) + 3.

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In parallelogram RSTU if UV = 12 Find US
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7- a. What is the radius of the circle with center (3,10) that passes through (12,12)?
loris [4]

Answer: a. Radius of circle = \sqrt{85}

b. The equation of this circle : (x-3)^2+(y-10)^2=85

Step-by-step explanation:

Given : Center of the circle = (3,10)

Circle is passing through (12,12).

a. To find the radius we apply distance formula (∵ Radius is the distance from center to any point ion the circle.)

Radius of circle = \sqrt{(12-3)^2+(12-10)^2}

Radius of circle = \sqrt{(9)^2+(2)^2}=\sqrt{81+4}=\sqrt{85}

i.e. Radius of circle = \sqrt{85}

b. Equation of a circle = (x-h)^2+(y-k)^2=r^2 , where (h,k)=Center and r=radius of the circle.

Put the values of (h,k)= (3,10) and r= \sqrt{85} , we get

(x-3)^2+(y-10)^2=(\sqrt{85})^2

(x-3)^2+(y-10)^2=85

∴  The equation of this circle :(x-3)^2+(y-10)^2=85

6 0
3 years ago
For the equation 8x + 2y = 16 What is the slope? What is the y-intercept (write as an ordered pair)? What is the x-intercept (wr
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Answer:

Step-by-step explanation:

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slope is -4

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