H = 151t - 16t²
The height of the ball when it return to the ground will be 0
0 = 151t - 16t²
The zero product property is that when two numbers are being multiplied and the product is 0, one of them must be equal to 0. Therefore, we can factorize this equation:
16t² - 151t = 0
t(16t - 151t) = 0
By the zero product property:
t = 0 or 16t - 151 = 0
So t = 0 or t = 9.44 seconds
The first solution is before he releases the ball and the second is when the ball comes back to the ground. Thus, the ball's air time is 9.44 seconds.
Answer:
I think the answer is D
Step-by-step explanation:
SOHCAHTOA
sin- Opposite and hypotenuses
Cos- Adjacent and Hypothesis
Tan- Opposite and adjacent
DE is opposite and DF is hypotenuses
Suppose the number is y >>>>>So y/2 +2y/3 <14
multiply both sides by 6>>>>>>>>>. 6y/2 +6x2y/3 <14x6
3y + 4y < 84
7y <84
y <84/7
y < 12
The whole entire canvas area - 660 inches
Area without the rose - 462 inches
