Colonization of aerobic coliform and Bacteroides
Answer:
700
Explanation:
If from the question the price per unit of fertilizer, p(x) = 300 - 0.1x
The cost of x units of fertilizer = C(x) = 15000 + 125x + 0.025x^2
And we know that Profit = Revenue - Cost
Revenue for x units of fertilizer R(X) = x*p(x)
= 300x - 0.1x^2
Hence Profit: P(x) = R(x) - C(x)
= [300x - 0.1x^2] - [15000 + 125x + 0.025x^2]
= -0.125x^2 + 175x - 15000
To determine critical values
P'(x) = -0.25x + 175 = 0
Thus x = 175/0.25
x = 700
To maximize profit, the manufactures must produce 700 units of fertilizers
Answer:
Mass/mass percent concentration means the mass of the solute/mass of the solution times 100. You know both the mass of the solute (0.870 g protein) and the mass of the solution (10.279 g solution). So divide and multiply your result by 100. (0.870 / 10.279 * 100)
Explanation:
Answer:
Air masses are characterized by their temperature and humidity properties. The properties of air masses are determined by the the underlying surface properties where they originate. ... Upon movement, air masses displace residual air over locations thus changing temperature and humidity characteristics.
Explanation:
