Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
Answer:
first we will make them like fractions
so 1/5= 2/10 so it will be
2/10+3/10= 5/10
HOPE IT HELPS
mark as brainliest
Answer:
vertical maybe if try it and see
Answer:
Step-by-step explanation:
Given:
Length of a rectangle solid = 3 m
Width of a rectangle solid = 0.6 m
Height of a rectangle solid = 0.4 m
To find: Volume of the solid
Solution:
Volume of the solid = length × breadth × height
So, the number of cubic meters in the volume of the solid is
Answer:D
Step-by-step explanation:
