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RoseWind [281]
3 years ago
14

WILL MARK BRAINLIEST

Mathematics
1 answer:
melisa1 [442]3 years ago
3 0

Answer:

d = \frac{1}{4}

Step-by-step explanation:

Given

= 16(d + 1) = - 20 ← distribute parenthesis on left side

- 16d - 16 = - 20 ( add 16 to both sides )

- 16d = - 4 ( divide both sides by - 16 )

d = \frac{-4}{-16} = \frac{1}{4}

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A stick is 9 m long. A rope is 2 times as long as the stick. If the rope is divided into 3 pieces, how many meters long is each
givi [52]
The length of rope(consist of 3 pieces)=9*2=18m
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6 0
2 years ago
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At a diner, Hailey's lunch cost $6.75. Her sister's lunch cost $5.95. After lunch they each had a frozen yogurt that cost the sa
aivan3 [116]

Answer:

Each cost 2.50$

Step-by-step explanation:

6.75+5.95=12.7

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Each cost 2.50$

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3 years ago
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10. Three kinds of teas are worth $4.60 per pound, $5.75 per pound, and $6.50 per pound. They are to be
zepelin [54]

Answer:

The mass of the $4.60/lb tea that should be used in the mixture is 10 lb

The mass of the $5.75/lb tea that should be used in the mixture is 8 lb

The mass of the $6.50/lb tea that should be used in the mixture is 2 lb

Step-by-step explanation:

The parameters of the question are;

The worth of the three teas are

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of the mixture of the three teas = 20 lb

The worth of the mixture of the three teas = $5.25 per pound = $5.25/lb

The amount of the $4.60 in the mixture = The sum of the amount of the other two teas

Therefore, given that the mass of the mixture = 20 lb, we have in the mixture;

The mass of tea A + The mass of Tea B + The mass of Tea C = 20 lb

The mass of tea A = The mass of Tea B + The mass of Tea C

Therefore;

The mass of tea A + The mass of tea A = 20 lb

2 × The mass of tea A in the mixture = 20 lb

The mass of tea A in the mixture = 20 lb/2 = 10 lb

The mass of tea A in the mixture = 10 lb

The mass of Tea B + The mass of Tea C = The mass of tea A = 10 lb

The mass of Tea B + The mass of Tea C = 10 lb

The mass of Tea B  = 10 lb - The mass of Tea C

Where the mass of Tea C in the mixture = x, we have;

The mass of Tea B in the mixture = 10 lb - x

The cost of the 10 lb of tea A = 10 × $4.60 = $46.0

The worth of the tea mixture = 20 × $5.25 = $105

The worth of the remaining 10 lb of the mixture comprising of tea A and tea B is given as follows;

The worth of Tea B + The worth of Tea C in the mixture = $105.00 - $46.00 = $59.00

Therefore, we have;

x lb × $6.50/lb + (10 - x) lb × $5.75/lb = $59.00

x × $6.50 - x × $5.75 + $57.50 = $59.00

x × $0.75 = $59.00 -  $57.50 = $1.50

x =  $1.50/$0.75 = 2 lb

∴ The mass of Tea C in the mixture = 2 lb

The mass of Tea B in the mixture = 10 lb - x = 10 lb - 2 lb = 8 lb

The mass of Tea B in the mixture = 8 lb

Therefore, since we have;

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of tea A in the mixture = 10 lb

The mass of tea B in the mixture = 8 lb

The mass of tea C in the mixture = 2 lb, we find;

The mass of the $4.60/lb tea that should be used in the mixture = 10 lb

The mass of the $5.75/lb tea that should be used in the mixture = 8 lb

The mass of the $6.50/lb tea that should be used in the mixture = 2 lb.

6 0
2 years ago
Rewrite quadratic equation<br> -×^2+2x-10
Lostsunrise [7]
It has no solution because it is not factorable 
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the men's world record for the high jump is 2.45 meters. A puma can jump about 1.9 times as high. what is the highest a puma can
Dmitry [639]
U could answer that question by adding 2.45+1.9=4.35
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3 years ago
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