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dedylja [7]
3 years ago
10

Is this answer correct?

Mathematics
2 answers:
katrin [286]3 years ago
6 0

Answer:

yes

Step-by-step explanation:

12345 [234]3 years ago
3 0
Yes this answer is correct
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Fie A, B, C, D patru puncte necoplanare.
rodikova [14]

Answer:

Hlooo em dng like the same time as a great day of the same time as a great day of the same time as a great day may I have a good time for

8 0
2 years ago
What is the measure of the third angle?
SCORPION-xisa [38]
The total amount of degrees in a triangle is 180. All three angles should add up to 180˚

We know that 40+60 = 100

The next step is to do 180-100 to get the other angle.
180-100 = 80

So the measure of the third angle is 80˚

Hope this helps!

(Also if you want to do this in one equation, you would do 40+60+x = 180
40+60+x = 180
100+x = 180 (combine like terms)
x = 80 (Subtract 100 from both sides)
7 0
3 years ago
WILL GIVE BRAINIEST AND 30 POINTS PLEASE ONLY ANSWER WITH AN ANSWER
alexandr402 [8]

Answer:

Step-by-step explanation:

1)13   2)-22 7/9   3)37.6   4)-16   5)1.75   6)-12    7).46   8)4.7   9)-21.42                  u can do ten I have to go to class

8 0
3 years ago
How to do this problem
Maslowich

Answer:

1 tens   3 ones

Step-by-step explanation:

All you do is count the numbers in the place value chart.

Since 31-18=13, all you do is count 10+1+1+1=13.

3 0
3 years ago
Question 4 This question has two parts. First, answer Part A. Then, answer Part B. Part A Fill in the blank question. COLLEGE LI
Annette [7]

The equation that models the number of students who live in apartments will be 6n + 15

<h3>How to illustrate the equation?</h3>

Total number of students T = 17n + 23

Students who live in dorm rooms on campus D = 11n + 8.

Therefore, the students who live in apartments will be:

= 17n + 23 - (11n + 8)

= 6n + 15

In order to predict the number of students who will live on campus in 2020, we will need the students that do not share dorm rooms.

Learn more about equations on:

brainly.com/question/2972832

#SPJ1

7 0
2 years ago
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