That's not true. 56 is 10 more than 46. 46 +10 is 56.
Answer:
an = (1 + 2·(n - 1))/2^(n - 1) = 2^(1 - n)·(2·n - 1)
sn = 6 - 2·0.5^n·(2·n + 3)
Answer:
t = (C - 3*A)/B + 3
Step-by-step explanation:
Given in the question that,
the speed with which canoe travelled for first 3 hours = A
the speed with which he travelled for any and all time thereafter = B
As we do not know the values of A, B, or C, so the answer will be an expression for C in terms of A and B.
<h3>Formula to use</h3>
distance = speed x time
C = A*3 + B*(t-3)
Rearranging and solving for t
C - (A*3) = B*(t-3)
C - (A*3) = Bt - B3
C - (A*3) + B3 = Bt
t = C - (A*3) + B3 / B
or
t = (C - 3*A)/B + 3
Answer:
0.00000381469
Step-by-step explanation:
there u go
Answer:
The answer is c i believe
Step-by-step explanation:
