1 year ago

What is (x^-2 y^10)^2/x^5 y^-3 using only positive exponents

Mathematics

1 answer:

Eddi Din [679]1 year ago

8 0

Answer:

$\frac{(x^{ - 2}{y}^{10})^{2} }{ {x}^{5} {y}^{ - 3} } \\ \frac{ {x}^{ - 4} {y}^{20} }{ {x}^{5} {y}^{ - 3 } } \\ {x}^{ - 9} {y}^{23} \\ \frac{ {y}^{23} }{ {x}^{9} } \\ ans \: c$

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