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irina1246 [14]
2 years ago
13

What is (x^-2 y^10)^2/x^5 y^-3 using only positive exponents

Mathematics
1 answer:
Eddi Din [679]2 years ago
8 0

Answer:

\frac{(x^{ - 2}{y}^{10})^{2}  }{ {x}^{5}  {y}^{ - 3} }  \\   \frac{ {x}^{ - 4}  {y}^{20} }{ {x}^{5}  {y}^{ - 3  } }  \\   {x}^{ - 9}  {y}^{23} \\  \frac{ {y}^{23} }{ {x}^{9} }  \\ ans \: c

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Answer shown below

Step-by-step explanation:

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80 points!!! I desperately need help! tell me how to do this! PLZ<br>(4k+5)(k+1)=0
Len [333]

Lets solve your equation step by step:

(4k + 5)(k + 1) = 0



Step 1: Simplify both sides of the equation:

4k^2 + 9k + 5 = 0



Step 2: Factor left side of equation:

(4k + 5)(k + 1) = 0



Step 3: Set factors equal to 0:


4k + 5 = 0 or k + 1 = 0


k = - 5/4 or k = - 1






Answer: k = - 5/4 or k = - 1








Hope that helps!!!! ( Answer: k = -5/4 or k = -1)

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