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kirill115 [55]
3 years ago
13

Can y’all help please . i don’t know how to do this .

Mathematics
2 answers:
matrenka [14]3 years ago
6 0
I'll explain how, if you want the answers to fact check, ask in the comments.

If the first number is in the ones place, and there's no notation, it's 10^0 (number * 1), if the first number is in the tens place, it's 10^1 of the number if it was pushed back into the ones place. If the first number is in the hundreds place, it's 10^2 if it was...

You might get the idea, same applies to negative powers of 10:

If the first number is in the tenths place, it's 10^-1, if the beginning of the number was moved forwards into the ones place, and so on.

I hope I helped you, please ask questions if you need them, I might have delivered a confusing explanation.
algol133 years ago
5 0
For scientific notation you have to move your decimal to where you number value is between 1-10

so for example on number one you are going to have to move your decimal to the right 2 times to get 2.9 (a value between 1-10)

now you have to write it in scientific notation-ask yourself two questions: how many times did you move your decimal? we moved it 2 times in this problem. and was it to the right or to the left? if you moved it to the right (which is the direction we moved it in this problem) its going to be a negative exponent so our answer would be 2.9x10^-2

same thing with number 2 starting with 64,000 to get our value to a number between 1-10 we need to move our imaginary decimal at the end of our value 4 times to make 6.4

two questions:
how many times did we move it? 4
did we move it to the left or to the right? to the left (so our exponent is positive)

making our answer 6.4x10^4

if you want me to check your answers after you have finished let me know:)
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Answer:

1)0.1cm

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Step-by-step explanation:

6 0
3 years ago
(−5)3x7(yz)4 / (3)2x2y8z2
g100num [7]

Answer:

\dfrac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}=\dfrac{-5x^5z^2}{2y^4}

Step-by-step explanation:

Given:

The expression to simplify is given as:

\frac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}

In order to simplify this, we have to use the law of indices.

1. (ab)^m=a^mb^m

So, (yz)^4=y^4z^4

Substitute this value in the above expression. This gives,

=\dfrac{(-5)3x^7y^4z^4}{(3)2x^2y^8z^2}\\\\\\=\dfrac{-15x^7y^4z^4}{6x^2y^8z^2}......(-5\times 3=15\ and\ 3\times 2=6)

Now, we use another law of indices.

2. \frac{a^m}{a^n}=a^{m-n}

So,  \frac{x^7}{x^2}=x^{7-2}=x^5,\frac{y^4}{y^8}=y^{4-8}=y^{-4}, \frac{z^4}{z^2}=z^{4-2}=z^2

Substitute these values in the above expression. This gives,

=\frac{-15}{6}\times x^5\times y^{-4}\times z^2\\\\=\frac{-5x^5y^{-4}z^2}{2}

Finally, we further simplify it using the law a^{-m}=\frac{1}{a^m}

So, y^{-4}=\frac{1}{y^4}

Therefore, the given expression is simplified as:

\dfrac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}=\dfrac{-5x^5z^2}{2y^4}

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What is the weight of the cow?
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ExtremeBDS [4]

Answer:

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Step-by-step explanation:

The diagram is shown in the attachment.

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