Ask question

Ask question

All categories

3 years ago

9

Sally ran 2 % miles in 12 hour. What is her speed in miles per hour?

1 answer:

andreev551 [17]3 years ago

7 0

Answer:

Step-by-step explanation:

if you're saying she ran .2 miles in 12 hours

then she ran .016 miles per hour

if you're saying she ran 2 miles in 12 hours,

then she ran 1/3 mile per hour or 0.3333 miles per hour

You might be interested in

I need help asap plz

Lostsunrise [7]

Answer:

A

Step-by-step explanation:

The constant of proportionality is the ratio between the two proportional variables in a directly proportional relationship. In this case, the variables are $x$ and $y$ .

To find the constant of proportionality, all we have to do is divide any value of $y$ by its corresponding value of $x$ . Let's take the values in the first row of the table. We know that $x=2$ and $y=12$ , so the constant of proportionality is $\frac{y}{x}=\frac{12}{2} =6$ . Hope this helps!

7 0

3 years ago

If you have 25 apples and you take 324 how many will you have.

inessss [21]

You will have -299 apples.

8 0

3 years ago

Read 2 more answers

3. You have decided to wallpaper your rectangular bedroom. The dimensions are 12 feet 6 inches by 10 feet 6 inches by 8 feet 0 i

Shalnov [3]

Answer:

B. 5 rolls

Step-by-step explanation:

The areas of the room, not including the ceiling, are discriminated as follows:

Longer walls: $(12.5\times8)\times2=200ft^2$ (6 inches equals one foot)

Shorter walls: $(10.5\times8)\times2 = 168ft ^ 2$ (6 inches equals one foot)

Window area: $(4\times3)\times2 = 24ft ^ 2$

Door area: $(7\times3) = 21ft ^ 2$

Area that will be effectively covered:

Total area to wallpaper: $200 + 168 -24 -21 = 323ft ^ 2$

Amount of paper needed: $323\times1.1 = 355.3ft ^ 2$

$30in = 24in + 6in = 2ft + 0.5ft = 2.5ft.$ That is, the area of a roll of paper is $2.5\times30 = 75ft ^ 2$

Number of rolls needed:

$\frac{355.3}{75} = 4.73$ rolls

5 0

3 years ago

Read 2 more answers

Factor the polynomial below. 9x^2-1 A. (-1)(9x-1) B. (3x-1)(3x-1) C. (3x-1)(3x+1) D. (x-1)(9x+1)

telo118 [61]

Answer:

(3x-1) (3x+1)

Step-by-step explanation:

9x^2-1

Rewriting as

(3x)^2 - 1^2

This is the difference of squares

a^2 - b^2 = (a-b)(a+b)

(3x-1) (3x+1)

6 0

3 years ago

Arrange the cones in order from lease volume to greatest volume

bearhunter [10]

Answer:

Volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

$d_{1} = 20\ and\ h_{1}=12$

$d_{2} = 18\ and\ h_{2}=10$

$r_{3} = 10\ and\ h_{3}=9$

$r_{4} = 11\ and\ h_{14}=9$

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for $d_{1} = 20\ and\ h_{1}=12$

$r_{1} = \frac{d_{1}}{2}$

$r_{1} = \frac{20}{2}=10\ units$

$V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}$

$V_{1}=\pi (10)^{2} \frac{12}{3}$

$V_{1}=\pi\times 100\times 4$

$V_{1}=400\pi\ units^{3}$

Similarly, for volume of the cone for $d_{2} = 18\ and\ h_{2}=10$

$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

$V_{2}=\pi (9)^{2} \frac{10}{3}$

$V_{2}=\pi\times 81\times \frac{10}{3}$

$V_{2}=\pi\times 27\times 10$

$V_{2}=270\pi\ units^{3}$

Similarly, for volume of the cone for $r_{3} = 10\ and\ h_{3}=9$

$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

$V_{3}=\pi\times 300$

$V_{3}=300\pi\ units^{3}$

Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

7 0

3 years ago