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VARVARA [1.3K]
2 years ago
10

Find the value of X in the triangle shown.

Mathematics
1 answer:
zalisa [80]2 years ago
7 0
X = 12

Use the Pythagorean Theorem.
13^2 = 5^2 + x^2
169 = 25 + x^2
Subtract 25 from both sides.
144 = x^2
Take the square root.
12 = x
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Just tell me if these soccer balls show a reflection. Its for a math assignment i just need to know if this shows a reflection
lidiya [134]

Answer: Yes

Step-by-step explanation:

4 0
3 years ago
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Can someone explain how to do this please?
Rufina [12.5K]

for the columns where is less than or equal zero, use the first line of the function to calculate the value of f(x)

{ ( \frac{1}{3} ) }^{ - 2} - 1  = 9 - 1 = 8 \\ { ( \frac{1}{3} ) }^{ - 1}  - 1 = 3 - 1 = 2 \\ { ( \frac{1}{3} ) }^{ 0} - 1  = 1 - 1 = 0

for every x greater than zero, use the second line to determine the value

{3}^{1}  - 2 = 3 - 2 = 1 \\ {3}^{2}  - 2 = 9 - 2 = 7

hope this helps and gives some insight what to do.

if there are open questions left, feel free to ask them in the comments

have a beautiful day

-Alex

3 0
3 years ago
A physician orders 140mg of a medication to give orally. You have 125mg/5mL on hand. What is the correct dose of medication to g
adelina 88 [10]
<h2>Hello!</h2>

The answer is: The correct dose of medication to give is 5.6 mL

<h2>Why?</h2>

To solve this problem we need to establish a relationship between the prescripted medication and the available solution.

Let's write the needed equations to establish the relantionship:

\frac{125mg}{5mL}=1\\\\125mg=5mL

The available solution means 125 mg each 5 mL of solution, so:

\frac{125mg}{5mL}=\frac{140mg}{x}\\\\x*\frac{125mg}{5mL}=140mg\\\\x=140mg*\frac{5ml}{125mg}=\frac{700mg*mL}{125mg}=5.6mL

Hence, the correct dose of medication to give is 5.6 mL of the 125 mg/5mL solution.

Have a nice day!

3 0
3 years ago
Solve for t and find the value for t if I= 115, P=650, r=5%
Brrunno [24]
P=650
R= 5% annually= 0.05
T=1 month=1/12 year

Sl=Prt=650*0.05*1/12= $2.70
So the answer would be 2.7 or 2.70
5 0
3 years ago
Can someone help me with this?​
Anna35 [415]

Answer:

Let 'a' be the first term, 'r' be the common ratio and 'n' be the number of terms

Series = 2+6+18.......= 2+2•3¹+ 2•3².......= 728

Now,

Sum =  \frac{a( {r}^{n} - 1) }{(r - 1)}   \\

So,

\frac{a( {r}^{n} - 1)}{(r - 1)}  = 728 \\  \frac{2( {3}^{n} - 1) }{(3 - 1)}  = 728 \\  \frac{2( {3}^{n} - 1) }{2}  = 728 \\  {3}^{n}  - 1 = 728 \\ {3}^{n}=728+1\\ {3}^{n}  = 729 \\  {3}^{n}  =  {3}^{6}  \\ \boxed{ n = 6}

Therefore, number of terms is 6

  • 6 is the right answer.
3 0
3 years ago
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