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sweet-ann [11.9K]
3 years ago
5

What percent of Zn3(PO4)2 is zinc?

Chemistry
1 answer:
DochEvi [55]3 years ago
5 0

16.94 % Zn

Explanation:

First we need the molar weight of the  Zn₃(PO₄)₂:

molar weight of Zn₃(PO₄)₂ = atomic weight of Zn × 3 + atomic weight of P × 2 + atomic weight of O × 4 × 2

molar weight of Zn₃(PO₄)₂ = 65.4 × 3 + 31 × 2 + 16 × 4 × 2 = 386 g/moles

Taking in account weight of 1 mole of Zn₃(PO₄)₂ we devise the following reasoning:

if         386 g of Zn₃(PO₄)₂ contains 65.4 g of Zn

then    100 g of Zn₃(PO₄)₂ contains X g of Zn

X = (100 × 65.4) / 386 = 16.94 % Zn

Learn more about:

percent composition

brainly.com/question/419592

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5 0
3 years ago
Use IUPAC rules to name this compound. A) nitrogen iodide B) nitrogen triiodide C) mononitrogen iodide D) mononitrogen triiodide
Mariulka [41]

Answer:

Name of the compound is Nitrogen triiodide.

Explanation:

According to the IUPAC rules, to naming of the compound the following formula can be applied.

Prefix + Name of first element + Base name element of second element + Suffix.

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Here, iodine is in ionic form therefore, it becomes iodide. and then suffix will be added in front of the halogen.

Therefore, name of the compound will be  Nitrogen triiodide..

3 0
3 years ago
Read 2 more answers
how many moles of gas does it take to occupy 120 liters at a pressure of 2.3 atmospheres and a temperature of 340 K?
dezoksy [38]
Data:

P (pressure) = 2.3 atm
V (volume) = 120 L
T (temperature) = 340 K
n (number of mols) = ?
R (Gas constant) = 0.082 (atm*L/mol*K)

Formula: 

p*V = n*R*T

Solving:
p*V = n*R*T
2.3*120 = n*0.082*340
276 = 27.88n
27.88n = 276
n = \frac{276}{27.88}
n = 9.89956...\to \boxed{\boxed{n\approx 9.90\:mols}}\end{array}}\qquad\quad\checkmark


7 0
4 years ago
The______ the forces among the particles in a sample of matter, the more rigid the matter will be.
Alexus [3.1K]

Answer:

Stronger!

Explanation:

The <u>stronger</u> the forces among the particles in a sample of matter, the more rigid the matter will be.

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4 years ago
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