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sweet-ann [11.9K]
3 years ago
5

What percent of Zn3(PO4)2 is zinc?

Chemistry
1 answer:
DochEvi [55]3 years ago
5 0

16.94 % Zn

Explanation:

First we need the molar weight of the  Zn₃(PO₄)₂:

molar weight of Zn₃(PO₄)₂ = atomic weight of Zn × 3 + atomic weight of P × 2 + atomic weight of O × 4 × 2

molar weight of Zn₃(PO₄)₂ = 65.4 × 3 + 31 × 2 + 16 × 4 × 2 = 386 g/moles

Taking in account weight of 1 mole of Zn₃(PO₄)₂ we devise the following reasoning:

if         386 g of Zn₃(PO₄)₂ contains 65.4 g of Zn

then    100 g of Zn₃(PO₄)₂ contains X g of Zn

X = (100 × 65.4) / 386 = 16.94 % Zn

Learn more about:

percent composition

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