Fe is undergoing oxidation while S is undergoing reduction
<h3>What is oxidation-reduction reaction?</h3>
Oxidation-reduction reaction can simply be defined as a special type of chemical reaction in which the oxidation states of substrate change. Oxidation is the
So therefore, Fe is undergoing oxidation while S is undergoing reduction
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Answer:
x=4
Explanation:
distribute-
2x+15x-21=47
combine like terms-
17x-21=47
add 21 to both sides
17x=68
Divide 17 from both sides
x=4
Answer:
Since both H2 and H2O have the same ratio in the balanced equation, if you have 20 moles of H2 you will also get 20 moles of H20.
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Answer:
Explanation:
You can deal with this question using two different but related approachs.
1) <u>First approach: 1 mole of gas at 1 atm and 0°C occupy 22.4 liter</u>.
With that you can set a proportion:
- 1 mole / 22.4 liter = 2.00 / V
⇒ V = 2.00 mole × 22.4 liter / 1 mole = 44.8 liter.
<u>2) Second approach: use ideal gas equation:</u>
⇒ V = nRT / p
- V = 2.00 moles × 0.0821 atm-liter / K-mol × 273.15 K / 1 atm = 44.85 liter ≈ 44.9 liter.
There, the two calculations yield the same result, although the second one is more accurate only if you need to use 3 or more significant digits, which is not correct in this case.
If you measure the presure as 1.0 atm (two significant digits) and the temperature as 0.0 °C (two significant digits), the volume must be resported with two significant digits, which yileds to the same result with both calculations: 45 liter.
1.50*10^23 molecules/ (6.02*10^23 molecules/mol)= 0.249 mol.
There is 0.249 mol in 1.50*10^23 molecules~