Answer:
Concentration of product at equilibrium ;
![[H^+]=0.0000229 M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.0000229%20M)
![[CN^-]=0.0000229 M](https://tex.z-dn.net/?f=%5BCN%5E-%5D%3D0.0000229%20M)
Explanation:
initially
0.85 M 0 0
(0.85-x)M x x
The equilibrium constant of reaction = 
The expression of an equilibrium cannot can be written as:
![K_c=\frac{[H^+][CN^-]}{[HCN]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH%5E%2B%5D%5BCN%5E-%5D%7D%7B%5BHCN%5D%7D)
Solving for x:
x = 0.0000229
Concentration of product at equilibrium ;
Explanation:
The pure form of water has a boiling point of 100°C. Boiling point is a physical property of matter and it shows that at such temperature, a liquid substance will change state to vapor.
Pure water is made up of 2 atoms of hydrogen and 1 atom of oxygen. The only intermolecular forces between them is the hydrogen bonds that must be broken for the water to boiling off.
In hydrate, water is present in another form. The water is attached to another compound.
For a pure liquid, the they have reasonably constant boiling point and low boiling range.
Impurities such as the other part of the hydrate causes the elevation of the boiling point and the widening of the boiling range for impure substances.
We are no longer dealing with just hydrogen bonds, other molecular interactions are now involved and they need to be accounted for.
learn more:
Pure substances brainly.com/question/1832352
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