Assuming that means 1.10^t:
0.10 is for years. To get months divide by 12.
0.10/12 = 0.0083333...
And (1+0.083333...) = 1.0833333. (You will have to multiply t by 12 also to get it in terms of months)
(1.0833333)^12t
Answer:
40 centimeters square.
Step-by-step explanation:
Area= length × width
8×5=40
Have a nice day
Answer:
About 99.7% of births would be expected to occur within 51 days of the mean pregnancy length
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Standard deviation = 17.
About what percentage of births would be expected to occur within 51 days of the mean pregnancy length?
51/17 = 3.
So, within 3 standard deviations of the mean.
About 99.7% of births would be expected to occur within 51 days of the mean pregnancy length
Answer:
wha?
Step-by-step explanation:
<span> (256 • (x3) - ( 2^2• 5^3 y^3)
______________________________________________________________
</span><span> 2^8 x^3 - ( 2^2 • 5^3 y^3)
</span>
256x^3 - 500y^3 = 4 • (64x^3 - 125y^3)<span>
</span><span>
64x^3 - 125y^3
</span>______________________________________________________________
<span>final factoization:
(4x - 5y) • </span><span> (16x^2 + 20xy + 25y^2)</span><span> </span>
