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MariettaO [177]
3 years ago
11

The quotient of 5n^2(m^2+2m-3)/10n(m^2-3m+2) divided by n^2(m^2-3m-18)/4n^2(m^2-8m+12)

Mathematics
1 answer:
slavikrds [6]3 years ago
7 0
\dfrac{ 5n^2(m^2+2m-3)}{10n(m^2-3m+2)} \div  \dfrac{n^2(m^2-3m-18)}{4n^2(m^2-8m+12)}

\dfrac{ 5n^2 (m + 3)(m - 1)}{10n( (m - 1)(m - 2)} \div  \dfrac{n^2(m + 3)(m - 6)}{4n^2(m - 2)(m - 6)}

\dfrac{ 5n^2 (m + 3)(m - 1)}{10n( (m - 1)(m - 2)} \times  \dfrac{4n^2(m - 2)(m - 6)}{n^2(m + 3)(m - 6)}

= 2n
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25% of all who enters a race do not complete. 30 haveentered.
nikklg [1K]

Answer:

The probability that exactly 5 are unable to complete the  race is 0.1047

Step-by-step explanation:

We are given that 25% of all who enters a race do not complete.

30 have entered.

what is the probability that exactly 5 are unable to complete the  race?

So, We will use binomial

Formula : P(X=r) =^nC_r p^r q^{n-r}

p is the probability of success i.e. 25% = 0.25

q is the probability of failure =  1- p  = 1-0.25 = 0.75

We are supposed to find the probability that exactly 5 are unable to complete the  race

n = 30

r = 5

P(X=5) =^{30}C_5 (0.25)^5 (0.75)^{30-5}

P(X=5) =\frac{30!}{5!(30-5)!} \times(0.25)^5 (0.75)^{30-5}

P(X=5) =0.1047

Hence the probability that exactly 5 are unable to complete the  race is 0.1047

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