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MariettaO [177]
3 years ago
11

The quotient of 5n^2(m^2+2m-3)/10n(m^2-3m+2) divided by n^2(m^2-3m-18)/4n^2(m^2-8m+12)

Mathematics
1 answer:
slavikrds [6]3 years ago
7 0
\dfrac{ 5n^2(m^2+2m-3)}{10n(m^2-3m+2)} \div  \dfrac{n^2(m^2-3m-18)}{4n^2(m^2-8m+12)}

\dfrac{ 5n^2 (m + 3)(m - 1)}{10n( (m - 1)(m - 2)} \div  \dfrac{n^2(m + 3)(m - 6)}{4n^2(m - 2)(m - 6)}

\dfrac{ 5n^2 (m + 3)(m - 1)}{10n( (m - 1)(m - 2)} \times  \dfrac{4n^2(m - 2)(m - 6)}{n^2(m + 3)(m - 6)}

= 2n
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