All categories

3 years ago

The quotient of 5n^2(m^2+2m-3)/10n(m^2-3m+2) divided by n^2(m^2-3m-18)/4n^2(m^2-8m+12)

1 answer:

7 0

$\dfrac{ 5n^2(m^2+2m-3)}{10n(m^2-3m+2)} \div \dfrac{n^2(m^2-3m-18)}{4n^2(m^2-8m+12)}$

$\dfrac{ 5n^2 (m + 3)(m - 1)}{10n( (m - 1)(m - 2)} \div \dfrac{n^2(m + 3)(m - 6)}{4n^2(m - 2)(m - 6)}$

$\dfrac{ 5n^2 (m + 3)(m - 1)}{10n( (m - 1)(m - 2)} \times \dfrac{4n^2(m - 2)(m - 6)}{n^2(m + 3)(m - 6)}$

$= 2n$

You might be interested in

Which can be the first step in finding the equation of the line that passes through the points (5, -4) and (-1, 8) in slope-inte

abruzzese [7]

Answer:

y = -2x + 6

Step-by-step explanation:

Slope = (-4 - 8)/(5 + 1)

= -12/6

= -2

Equation

y - 8 = -2(x + 1)

y - 8 = -2x - 2

y = -2x + 6 <-----------slope-intercept form

7 0

3 years ago

Tamika ran 120 meters in 21.6 seconds. Enrique ran 120 meters in 22.4

Alexus [3.1K]

Tamika ran the fastest time at 21.6 seconds in 120 meters because the faster you run the less time you have on your timer.

8 0

3 years ago

A student needs to make a square cardboard piece. The cardboard should have a perimeter equal to at least 92 inches. The functio

Illusion [34]

Answer:

$s\geq 23$

Step-by-step explanation:

We are given that a student needs to make a square cardboard piece.

Perimeter of cardboard should be equal to atleast 92 inches

We have to find that which shows reasonable domain for f(s)

Let s be the side of square cardboard

We know that perimeter of square =f(s=) $4\times side$

Then, perimeter of cardboard= $4s$

$4s\geq 92$

Dividing by 4 on both sides

$s\geq 23$

Hence, the domain of function $[23,\infty)$

Therefore, option d is true.

Answer:d: $s\geq 23$

6 0

4 years ago

Which point lies on the graph of f(x) = -2(x + 3) – 5

Assoli18 [71]

well from my understanding of the problem and calculations i would say.. (-5.5,0)

8 0

3 years ago

Read 2 more answers

Kayson is looking at two buildings, building A and building B, at an angle of elevation of 73' Building A is 30 feet away, and b

wlad13 [49]

Answer:

Building B, it is around 16 35 feet taller than building A ( C )

Step-by-step explanation:

<u>Calculating the height of Building A </u>

Height = opposite ( ? )

∅ = 73°

base/adjacent = 30 ft

∴ Height = Tan 73° * base

= 3.2709 * 30 = 98.127 ft

<u>Calculating the height of building B </u>

∅ = 73°

base/adjacent = 35 ft

∴ height = Tan 73° * base

= 3.2709 * 35 = 114.4815

Therefore we can say Building B is Taller by approximately 16.35 feet

7 0

3 years ago