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3 years ago

Three times the sum of a number and eight is four more than the number. find the number

Mathematics

1 answer:

docker41 [41]3 years ago

7 0

Answer:

3(x+8)=4+x

distribute the 3 by multiplying it with the x and the 8

3x+24=4+x

subtract x from both sides

2x+24=4

subtract 24 from both sides

2x=4-24

2x=-20

divide each side by 2

leaving the variable isolated

x=-10

Step-by-step explanation:

It is important to balance each side by doing the same to both sides such as at the end divide both sides by 2.

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Find the inverse Laplace transform f(t) of the function F(s). Write uc for the Heaviside function that turns on at c, not uc(t).

zzz [600]

Answer:

F(t) $=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}$

Step-by-step explanation:

We have given $F(S)=\frac{7e^{-7s}}{s^2-49}$

Now $F(S)=e^{-7s}G(s)$

Here $G(S)=\frac{7}{S^2-49}$

Now first find the Laplace inverse of G(S)

Using partial fraction

$\frac{7}{(s+7)(s-7)}=\frac{A}{(S+7)}+\frac{B}{S-7}$

$7=A(S-7)+B(S+7)$

On comparing the coefficient

$A=\frac{1}{2}$ and $B=\frac{-1}{2}$

On putting the value of A and B

$G(S)=\frac{-1}{2(S+7)}+\frac{1}{2(S+7)}$

Taking inverse Laplace

$G(t)=\frac{-1}{2}e^{7t}+\frac{1}{2}e^{-7t}$

Now in G(s) there is onether term $e^{-7s}$

So F(t) $=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}$

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Three times the sum of a number and eight is four more than the number. find the number￼

Three times the sum of a number and eight is four more than the number. find the number