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crimeas [40]
3 years ago
7

Can someone help with this pleasee?

Mathematics
1 answer:
enot [183]3 years ago
3 0

Answer:

That is so easyyyyyyyyy

Step-by-step explanation:

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Hello,

m\ \widehat{ABC}=x\\m\ \widehat{BAC}=2*x\\\\So:\\ x+2x=90^o\\x=30^o\\

cos(30^o)=\dfrac{\sqrt{3} }{2} \\

In the triangle ABC,

cos(30^o)=\frac{BC}{BA} \\\\BA=\dfrac{cos(30^o)}{BC} \\\\BA=\frac{\dfrac{\sqrt{3} }{2} }{24} =16*\sqrt{3} \\\\

sin(30^o)=\dfrac{1 }{2} =\dfrac{AC}{AB} \\\\AC=\dfrac{1}{2} *16\sqrt{3} =8\sqrt{3}

In the triangle ACB,

cos(30^o)=\dfrac{AC}{AL} \\\\AL=\dfrac{8\sqrt{3} *2}{\sqrt{3} } =16\\

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2 years ago
Find the location of the x-intercept, the location of the y-intercept, and the slope for the line
I am Lyosha [343]

Answer:

x intercept  (15/4,0)

y intercept (0,2)

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15y − 8x = 30.

To find the x intercept, set y =0

15(0) -8x = 30

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Divide each side by 8 to solve for x

8x/8 = 30/8

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To find the y intercept, set x =0

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To find the slope we solve the equation for y

15y − 8x = 30.

Add 8x to each side

15y − 8x+8x =8x +30.

15y = 8x +30

Divide each side by 15

15y/15 = 8x/15 +30/15

y = 8/15x +2

The slope is 8/15

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Gnesinka [82]

Answer:

2

Step-by-step explanation:

8 0
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