Answer:
From a <u>table</u>, for an ordered pair (0, y), <em>y</em> will not be <u>zero</u>. From a <u>graph</u>, the y-intercept will not be <u>zero</u>. From an equation, it will have the form, y = mx + b where b is <u>≠ 0</u>.
Step-by-step explanation:
- From a <u>table</u>, for an ordered pair (0, y), <em>y</em> will not be <u>zero</u>. If there is not a constant rate of change in the data displayed in a table, then the table represents a nonlinear nonproportional relationship.
- From a <u>graph</u>, the y-intercept will not be <u>zero</u>. This means that it doesn't contain or go through the origin.
- From an equation, it will have the form, y = mx + b where b is <u>≠ 0.</u> (not equal to zero). If an equation is not a linear equation, it represents a nonproportional relationship. A <u>linear equation</u> of the form y = mx + b may represent either a <em>proportional</em> (b = 0) or <em>nonproportional</em> (b ≠ 0) relationship. Therefore, when b ≠ 0, the relationship between <em>x</em> and <em>y</em> is <u>nonproportional</u>.
Step-by-step explanation:
Since both terms are perfect squares, factor using the difference of squares formula, a 2 − b 2 = ( a + b ) ( a − b ) where a = 7 and b = a + x . − ( 7 + a + x ) ( a + x − 7 )
Answer:
your answers are in the correct order.
D,A,C,E,B
I'm pretty sure its B but I would double check before you put the answer in :)