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jolli1 [7]
3 years ago
8

For every gallon of water in a swimming pool, you’ Instructed to add four grams of chlorine. How many grams of chlorine would yo

u add to a pool containing 13 gallons of water?
Mathematics
2 answers:
kozerog [31]3 years ago
8 0

<u>Answer:</u>

52 grams

<u>Step-by-step explanation:</u>

This problem can be solved simply by applying the ratio method.

We know that 1 gallon of waters requires 4 grams of Chlorine in the swimming pool, so we can assume the number of grams of Chlorine required for 13 gallons of water to be x.

So we can write it as:

\frac{1 gallon of water}{13 gallons of water} = \frac{4g of Chlorine}{x}

So x will be equal to = 13 * 4 = 52

Therefore, 52 grams of Chlorine is required for 13 gallons of water in the swimming pool.

Kruka [31]3 years ago
7 0

Answer:

52

Step-by-step explanation:

Multiply grams per gallon times gallons to get grams.

4\,\dfrac{g}{gal}\times 13\,gal=4\times 13\,\dfrac{g\cdot gal}{gal}=52\,g

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3 years ago
What is the value of the correlation coefficient r of the data set?
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<u><em>Explanation</em></u>

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<em>(Please refer to the attached image for the table )</em>

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r= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{\sqrt{[n\Sigma x^2-(\Sigma x)^2][n\Sigma y^2-(\Sigma y)^2]}}\\ \\ r=\frac{7(1480)-(44)(183)}{\sqrt{[7(362)-(44)^2][7(6575)-(183)^2]}}\\ \\ r=\frac{10360-8052}{\sqrt{(598)(12536)}}\\ \\ r=\frac{2308}{\sqrt{7496528}}\\ \\ r=0.84

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