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jolli1 [7]
3 years ago
8

For every gallon of water in a swimming pool, you’ Instructed to add four grams of chlorine. How many grams of chlorine would yo

u add to a pool containing 13 gallons of water?
Mathematics
2 answers:
kozerog [31]3 years ago
8 0

<u>Answer:</u>

52 grams

<u>Step-by-step explanation:</u>

This problem can be solved simply by applying the ratio method.

We know that 1 gallon of waters requires 4 grams of Chlorine in the swimming pool, so we can assume the number of grams of Chlorine required for 13 gallons of water to be x.

So we can write it as:

\frac{1 gallon of water}{13 gallons of water} = \frac{4g of Chlorine}{x}

So x will be equal to = 13 * 4 = 52

Therefore, 52 grams of Chlorine is required for 13 gallons of water in the swimming pool.

Kruka [31]3 years ago
7 0

Answer:

52

Step-by-step explanation:

Multiply grams per gallon times gallons to get grams.

4\,\dfrac{g}{gal}\times 13\,gal=4\times 13\,\dfrac{g\cdot gal}{gal}=52\,g

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attached below is the detailed solution

M = \frac{152}{3}б

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3 years ago
Please help if you know the answer please!
quester [9]
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7 0
2 years ago
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Alexxx [7]

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2 years ago
A positive integer is 11 more than 18 times another. Their product is 6030. Find the two integers.
allsm [11]

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Step-by-step explanation:

y = 18x + 11

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x * (18x + 11) = 6030

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3 years ago
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