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qaws [65]
2 years ago
7

The table shows the weight of a newborn infant for its first year. During which three-month period was the infant's weight gain

the greatest?
0 Months: 7 1/4 lb

3 Months: 12 1/2 lb

6 Months: 16 5/8 lb

9 Months: 19 4/5 lb

12 Months: 23 3/20 lb
Mathematics
1 answer:
EastWind [94]2 years ago
4 0

Answer:

12,9,6

Step-by-step explanation:

12=23 3/20. 9=19 4/5. 6=16 5/8.

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Please show your work how you solved this step by step ! Please answer this !!
erastovalidia [21]

Answer:

2x^2

Step-by-step explanation:

8 0
3 years ago
Joslyn wants to buy 4 packs of pens for $12.00 each and a pack of pencils for &6.00. How much money does she need
seropon [69]
$54 is your answer

You multiply $12.00 by 4 packs of pens and then add $6.00 for the pencils.
8 0
3 years ago
HELPPP!!!
xxMikexx [17]

The angles ∠CFE and ∠AFB are vertically opposite angles. Then the value of x will be 6.

<h3>What is an angle?</h3>

Angle is the space between the line or the surface that meets.  And the angle is measured in degree. For complete 1 rotation, the angle is 360 degrees.

Vertically opposite angle - When two lines intersect, then their opposite angles are equal.

We know that the angle ∠DFE is 90°.

Then the sum of the angle ∠CFD and ∠DFE will be

∠CFD + ∠DFE = 27° + 90°

∠CFD + ∠DFE = 117°

Then the angles ∠CFE and ∠AFB are vertically opposite angles. Then we have

∠CFD = ∠DFE

Put the values

21x - 9 = 117

    21x = 126

        x = 6

More about the angled link is given below.

brainly.com/question/15767203

#SPJ1

8 0
2 years ago
1. What percent of 58 is 18?
malfutka [58]

In order to find the answer you will have too divide 58 by 18 and then divide what you get from that by 100 to get your answer.

100%/x%=58/18

(100/x)*x=(58/18)*x    

100=3.22222222222*x      

(3.22222222222) to get x

100/3.22222222222=x

x=31.0344827586

Therefore your answer is "31%."

Hope this helps.

8 0
3 years ago
I need help please help me thanks please
Vitek1552 [10]

so we have a table of values, with x,y coordinates, so let's use any two of those points to get the slope of the table and use the point-slope form to get its equation

~\hspace{2.7em}\stackrel{\textit{let's use}}{\downarrow }\qquad \stackrel{\textit{and this}}{\downarrow }\\\begin{array}{|lr|r|r|r|r|}\cline{1-6}x&0&1&2&3&4\\y&-1&3&7&11&15\\\cline{1-6}\end{array}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\(\stackrel{x_1}{1}~,~\stackrel{y_1}{3})\qquad(\stackrel{x_2}{4}~,~\stackrel{y_2}{15})

\stackrel{slope}{m}\implies\cfrac{\stackrel{rise}{\stackrel{y_2}{15}-\stackrel{y1}{3}}}{\underset{run}{\underset{x_2}{4}-\underset{x_1}{1}}}\implies \cfrac{12}{3}\implies 4\\\\\\% point-slope intercept\begin{array}{|c|ll}\cline{1-1}\textit{point-slope form}\\\cline{1-1}\\y-y_1=m(x-x_1)\\\\\cline{1-1}\end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{4}(x-\stackrel{x_1}{1})\\\\\\y-3=4x-4\implies y = 4x-1\implies \blacktriangleright  y = 4x+(-1)\blacktriangleleft

4 0
2 years ago
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