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Aleonysh [2.5K]
3 years ago
5

The length,AB of the rectangular lot is 1 foot less than two times its width, BC. If the perimeter of the rectangular lot 394 fe

et, what is the length, AB of the rectangular lot?
Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
6 0

Answer:

AB=131\ ft

Step-by-step explanation:

we know that

The perimeter of the rectangular lot is

P=2(AB+BC) ----> equation A

where

AB is the length

BC is the width

we have

AB=2BC-1 ---> equation B

P=394\ ft ----> equation C

substitute equation B and equation C in equation A

394=2(2BC-1+BC)

solve for BC

394=2(3BC-1)

394=6BC-2

6BC=396

BC=66\ ft

<em>Find the value of AB</em>

AB=2BC-1

AB=2(66)-1

AB=131\ ft

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\boxed{\sf Option \ 4}

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