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Aleonysh [2.5K]

3 years ago

5

The length,AB of the rectangular lot is 1 foot less than two times its width, BC. If the perimeter of the rectangular lot 394 fe

et, what is the length, AB of the rectangular lot?

1 answer:

r-ruslan [8.4K]3 years ago

6 0

Answer:

$AB=131\ ft$

Step-by-step explanation:

we know that

The perimeter of the rectangular lot is

$P=2(AB+BC)$ ----> equation A

where

AB is the length

BC is the width

we have

$AB=2BC-1$ ---> equation B

$P=394\ ft$ ----> equation C

substitute equation B and equation C in equation A

$394=2(2BC-1+BC)$

solve for BC

$394=2(3BC-1)$

$394=6BC-2$

$6BC=396$

$BC=66\ ft$

<em>Find the value of AB</em>

$AB=2BC-1$

$AB=2(66)-1$

$AB=131\ ft$

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