Question

The length,AB of the rectangular lot is 1 foot less than two times its width, BC. If the perimeter of the rectangular lot 394 feet, what is the length, AB of the rectangular lot?

Answer 1

Answer:

$AB=131\ ft$

Step-by-step explanation:

we know that

The perimeter of the rectangular lot is

$P=2(AB+BC)$ ----> equation A

where

AB is the length

BC is the width

we have

$AB=2BC-1$ ---> equation B

$P=394\ ft$ ----> equation C

substitute equation B and equation C in equation A

$394=2(2BC-1+BC)$

solve for BC

$394=2(3BC-1)$

$394=6BC-2$

$6BC=396$

$BC=66\ ft$

Find the value of AB

$AB=2BC-1$

$AB=2(66)-1$

$AB=131\ ft$