Question

This table gives a few (x,y) pairs of a line in the coordinate plane.

Answer 1

Answer:

x-intercept → (-5, 0)

Step-by-step explanation:

Let the equation of the line having pairs given in the table is,

y - y' = m(x - x')

m = slope of the line

(x', y') is a point lying on the line.

From the given table,

Two points (33, -22) and (52, -33) lie on the line.

Slope of the line = $\frac{y_2-y_1}{x_2-x_1}$

                        m = $\frac{-33+22}{52-33}$

                        m = $-\frac{11}{19}$

Equation of the line passing through (33, -22) and slope = $-\frac{11}{19}$ will be,

y + 22 = $-\frac{11}{19}(x - 33)$

For x-intercept y = 0,

0 + 22 = $-\frac{11}{19}(x-33)$

-38 = x - 33

x = -38 + 33

x = -5

Therefore, x-intercept of the line is (-5, 0).