Area of decagon is given by:
Area=1/2(nsr)
where:
n=number of sides
s=side length
r=height
thus the area will be given by:
Area=1/2(10*4*6.2)
Area=124 cm^2
If an items weight is 0 it would be like a peice of paper or cotten ball. when a cotten ball is weighed it does not affect anything. as when a peice of paper is wieghed it moves its meater 1 inch.
To solve this problem, we have to apply mole-concept to this and we would need the molar mass of AlCl3. 2g of AlCl3 contains 9.034*10^21 molecules.
<h3>Number of Molecules in 2g of AlCl3</h3>
The molar mass of AlCl3 is given as 133.34g/mol
Data;
- mass = 2g
- molar mass = 133.34g/mol
Using the mole concept, we can equate the molar mass to the number of molecules present in the entity.

If we equate this

From the calculations above, 2g of AlCl3 contains 9.034*10^21 molecules.
Learn more on mole concept here;
brainly.com/question/21150359
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3/7
6 divided by 2 equals 3
14 divided by 2 equals 7