Answer:
Yes it is,
Step-by-step explanation:
Degree 1 (Exp 1) and it has 2 elements (2X and 1)
Just do 1/8 times 1/8. Hope this helped !!
Answer:
7.3% percentage of the bearings produced will not be acceptable.
Step-by-step explanation:
Consider the provided information.
Average diameter of the bearings it produces is .500 inches. A bearing is acceptable if its diameter is within .004 inches of this target value.
Let X is the normal random variable which represents the diameter of bearing.
Thus, 0.500-0.004<X<0.500+0.004
0.496<X<0.504
The bearings have normally distributed diameters with mean value .499 inches and standard deviation .002 inches.
Use the Z score formula: 
Therefore



Now use the standard normal table and determine the probability of that a ball bearing will be acceptable.
We need to find the percentage of the bearings produced will not be acceptable.
So subtract it from 1 as shown.
1-0.9270=0.073
Hence, 7.3% percentage of the bearings produced will not be acceptable.
Answer:
yo! I dont know the **** answer
Step-by-step explanation:
To answer the question, we utilize the given data and solve for the number of customers left in the store after every 1 hour interval.
Initially, there were 75 customers.
1:00 to 2:00 : 75 + 30 - 12 = 93
2:00 to 3:00 : 93 + 14 - 8 = 99
3:00 to 4:00 : 99 + 18 - 30 = 87
4:00 to 5:00 : If the store does not accept any more customers except those who are already inside then, all 87 must leave between 4:00 to 5:00 in order to empty out the store by 5:00
ANSWER: (a) 4:00 to 5:00
(b) 87 customers